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3 years ago

Determine the perimeter of a triangle with sides that measure 16.2 inches, 10.04 inches and 12.2 inches.

Mathematics

1 answer:

Ksju [112]3 years ago

5 0

Answer:

Step-by-step explanation:

Solution,

The perimeter of a triangle=Sum of all sides

$16.2in+10.04in+12.2in\\=38.44inches$

Hope it will help you a lot.

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3 years ago

Read 2 more answers

Find a vector 3 units long in the opposite direction from v = 〈3, 1,-4).

lutik1710 [3]

Unit vector along the direction v = <3,1,-4> is :

$\hat{v} = \dfrac{3i + j -4k}{\sqrt{3^2 + 1^2 + 4^2}}\\\\\hat{v} = \dfrac{3i + j -4k}{5.1}$

So, unit vector opposing the $\hat{v}$ is :

$\hat{v'} = -\hat{v}\\\\\hat{v'} = -( \dfrac{3i + j -4k}{5.1})\\\\\hat{v'} = \dfrac{-3i - j +4k}{5.1}$

so, vector of magnitude 3 units in opposite direction from v is :

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3 years ago