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zlopas [31]
2 years ago
9

Whoever helps me with this I'll give brainliest and extra points! :)

Mathematics
1 answer:
Musya8 [376]2 years ago
6 0

What are the options

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Can someone help me with this question
Savatey [412]

x^2 + 9.5^2 = 11^2

x^2 + 90.25 = 121

x^2 = 30.75

x^2 = \sqrt{30.75}

x = 5.54cm

rounded: 5.5cm

answer: D

6 0
2 years ago
Is the sqrt of 102 a rational or irrational number?
lesantik [10]

Answer:

Yes, 102 isn't a square number (1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144) so the square root of 102 will keept going forever and is irrational.

Step-by-step explanation:

basically

4 0
3 years ago
If the store purchases a product at a wholesale cost of $1.65, and it is sold at $2.20, what is the gross profit percentage? (fo
Irina-Kira [14]
Using this formula, the gross profit percentage is approx. 75%
7 0
3 years ago
BRAINLIEST!!PLEASE HELP ME!!
pishuonlain [190]

Answer:


Step-by-step explanation:

The truck's fuel consumption is:

660 miles

---------------- = 7.33 miles per gallon.

90 gallons

Draw a set of coordinate axes, with # of gallons on the horiz. axis and distance traveled on the vertical axis.  Place a black dot at (0,0).  Starting at (0,0), draw in scale divisions that can accommodate 0-100 gallons.  Mark scale divisions on the vertical axis such that the maximum distance traveled is 800 miles.  Now draw a vertical line through 90 gallons and a horizontal line through 660 miles.  Draw a black dot where these two lines intersect.  Now draw a straight line through (0,0) and (90,660).  These two points are your intercepts, horiz. first and vert. second.

The domain is the set of numbers on the horiz. axis for which you have a graph (meaning that your function is defined).  Here your domain is

[0,90] gallons.  No function is defined for less than 0 gallons or more than 90 gallons.

The origin represents no fuel yet consumed and no distance yet traveled.

8 0
3 years ago
Can someone pls pls PLS, help me out? ASAP!! (Geometry)<br> “Complete the proof”
Maru [420]

1) \overline{AB} \perp \overline{BD}, \overline{AB} \cong \overline{DB}, \overline{AC} \cong \overline{DE} (given)

2) \angle ABD is a right angle (perpendicular lines form right angles)

3) \triangle ABD and \triangle DEB are right triangles (a triangle with a right angle is a right angle)

4) \triangle ABD \cong \triangle DEB (HL)

5) \angle ACB \cong \angle DEB (CPCTC)

8 0
1 year ago
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