The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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$880, $896, $914, $925, and $963
median = $914
mean = (896+925+880+963+914)/5 = 4578/5 = $915.6
$915.6 - $914 = $1.6
so mean is greater than median $1.6
answer is B. second choice
<span>The mean is $1.60 greater.</span>
Answer:
1.# = 119.2 2.# = 869.545454545 3.# = 443.66666666 4.# = 13501.3939394
Step-by-step explanation:
i don't know about the 2 one and 3 and 4 one that came up a very big number. I used a calculator though.exactly way you tired to tipe it in sorry it took so long to answer the problem!!!.
Answer:
The answer is A
Step-by-step explanation:
I solved using surface area
