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Harman [31]
2 years ago
12

An editor has a stack of k documents to review. The order in which the documents are reviewed is random with each ordering being

equally likely. Of the k documents to review, two are named “Relaxation Through Mathematics” and “The Joy of Calculus.” Give an expression for each of the probabilities below as a function of k. Simplify your final expression as much as possible so that your answer does not include any expressions in the form a b . (a) What is the probability that “Relaxation Through Mathematics” is first to review?
Mathematics
1 answer:
ladessa [460]2 years ago
8 0

Using the probability concept, it is found that there is a \mathbf{\frac{1}{k}} probability that “Relaxation Through Mathematics” is first to review.

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem:

  • There is a total of k documents to be reviewed, hence T = k.
  • Of those documents, 1 is named “Relaxation Through Mathematics”, hence D = 1

The <em>probability </em>is:

p = \frac{D}{T} = \frac{1}{k}

A similar problem is given at brainly.com/question/24483829

You might be interested in
Three missiles are fired at an enemy arsenal. The probabilities the individual missile will hit the arsenal are 0.75, 0.85, and
Fantom [35]
The probability that at least two of the missiles hit the arsenal:
P ( x ≥ 2 ) = P ( x = 2 ) + P ( x = 3 )
P ( x = 2 ) = 0.75 · 0.85 · 0.1 + 0.85 · 0.9 · 0.25 + 0.75 · 0.9 · 0.15 =
= 0.06375 + 0.10125 + 0.19125 = 0.35625
P ( x = 3 ) = 0.75 · 0.85 · 0.9 = 0.57375
P ( x ≥ 2 ) = 0.35625 + 0.57375 = 0.93
Answer:
The probability is 0.93 or 93%. 
3 0
3 years ago
Round to ten thousands 25497 54088
Inessa [10]
I think it's 254974090
4 0
3 years ago
The photo is clear now so what is answer to this question?
erik [133]

Answer:

x = 4

Step-by-step explanation: because 13 - 13 u cross them out and u get 17 subtract 13 and ounce u do them u get 4 so then now your left with x so u bring that down and then u get x = 4 hopefully i answered your question or answer have a nice day as well

5 0
3 years ago
What is this? anyone help​
qwelly [4]

Answer:

-a^2 -a -35

Step-by-step explanation:

a(4-a) -5(a+7)

Distribute

4a -a^2 -5a-35

Combine like terms

-a^2+4a -5a-35

-a^2 -a -35

4 0
4 years ago
A certain three​-cylinder combination lock has 60 numbers on it. To open​ it, you turn to a number on the first​ cylinder, then
statuscvo [17]

Answer:

(a) The number of different lock combinations is 216,000.

(b) The probability of getting the correct combination in the first try is \frac{1}{216000}.

Step-by-step explanation:

The lock has three-cylinder combinations with 60 numbers on each cylinder.

The procedure of the opening lock is to turn to a number on the first​ cylinder, then to a second number on the second​ cylinder, and then to a third number on the third cylinder.

The numbers can be repeated.

(a)

There are three cylinder combinations on the lock, each with 60 numbers.

It is provided that repetitions are allowed.

Then each cylinder can take any of the 60 numbers.

So there are 60 options for the first cylinder.

There are 60 options for the second cylinder.

And there are 60 options for the third cylinder.

So the total number of possible combinations is:

Total number of combinations = 60 × 60 × 60 = 216000.

Thus, the number of different lock combinations is 216,000.

(b)

The events of getting a correct combinations of the three​-cylinder combination lock implies that all the three cylinder are set at the correct numbers.

Each cylinder has 60 numbers.

This implies that there are 60 possible ways to get a correct number for the first cylinder.

The probability of getting the correct number for the first cylinder is:

P (Number on 1st cylinder is correct) = \frac{1}{60}.

Similarly for the second cylinder the probability of getting the correct number is:

P (Number on 2nd cylinder is correct) = \frac{1}{60}.

And similarly for the third cylinder the probability of getting the correct number is:

P (Number on 3rd cylinder is correct) = \frac{1}{60}.

So the probability of getting the correct combination in the first try is:

P (Correct combination in the 1st try) = \frac{1}{60}\times \frac{1}{60}\times \frac{1}{60}=\frac{1}{216000}.

Thus, the probability of getting the correct combination in the first try is \frac{1}{216000}.

7 0
3 years ago
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