Ask question

Ask question

All categories

2 years ago

6

Given that lines b and c are parallel, and the m<1=4x-30 and m<5=2x+50. Find the measure of angle 1 and measure of angle 7

Explain your reasoning and show your work.
tysm in advance

1 answer:

AfilCa [17]2 years ago

5 0

4x-30=2x+50
+30 +30

4x=2x+80
-2x -2x

2x=80
/2 /2

X=40

4(40)-30=130°

2(40)+50=130°

180-130=50°

Angle 7=50°

You might be interested in

Write h(x)=x2-6x + 3 in vertex form

Anna007 [38]

Answer: The vertex form is h(x)=(x-3)^2-6

Step-by-step explanation:

Using the complete the square method, first complete any squares

X^2-6x+(-3)^2-(-3)^2+3

Use the binomial formula

(x-3)^2 - (-3)^2 +3

Simplify

(x-3)^2-6

7 0

3 years ago

Given that f (x)=2x+5 and g(x)=x-7 solve for f (g (x)) when x=-3

Alexeev081 [22]

2(-3-7)+5= <span>2(-10)+5= -20 + 5= -15

-15 is your final answer</span>

7 0

3 years ago

What is the equivalent ratio of 1:2

Paraphin [41]

What the answers choices?

6 0

3 years ago

If cot theta= 4/3, find csc theta

Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

$csc^2\theta=cot^2\theta+1$

Knowing that $cot\theta=\frac{4}{3}$ :

Substitute it into $csc^2\theta=cot^2\theta+1$ :

$csc^2\theta=(\frac{4}{3})^2+1$

Simplify the expression:

$csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}$

Solve for $csc\theta$ . Apply square root at both sides of the expression:

$\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}$

$csc\theta=\frac{5}{3}$

8 0

3 years ago

describe a situation in which a formula could be used more easily if it were rearranged. Include the formula in your description

pshichka [43]

I need to find the length of something when I am given the volume, width, and height.

v=lwh
l = v/wh

Hope this helps!

5 0

3 years ago

Read 2 more answers