Can anyone help me?

At the start of the school year, students can pick to have either a black ID holder (B) or a red ID holder (R). Suppose that two

Makovka662 [10]

The sample space is nothing but ALL possible outcomes. In this case you have Black & Red id's. Then the sample space is {black, red}

3 0

3 years ago

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Brayden has 342 marbles in bags. If there are 9 marbles in each bag, how many bags of marbles does Brayden have If Brayden gives

Firlakuza [10]

Brayden has 38 bags.
After giving away 15 bags of marbles, Brayden is left with 23 bags.

To find out how many bags he has we do 342 divided by 9 which is 38.

To find out how many marbles are in 15 bags we do 15 x 9 which is 135.
We then do 342 - 135 to find out how many marbles he has left which is 207 and divide 207 by 9 to convert that into bags, which is 23.

8 0

3 years ago

What values of x make the equation x2 + 9x – 22 = 0 true? Check all that apply. –11 –2 0 2 11

Marat540 [252]

Answer: x = 2 ; -11 .
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Explanation:
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Given the equation:
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x² + 9x −<span> 22 = 0 ; Solve for: "x" ;
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Let us factor the "left-hand side" of the equation:
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"x</span>² + 9x −<span> 22" ;
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What are the factors of "-22"" that add up to "positive 9" ?
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Let us list the factors of "-22" :
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-2, 11; </span>→ -2 + 11 = 9 ;<span>
-11, 2; </span>→ -11 + 2 = -9 ;<span>
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So we have: "-2" and "11" ;
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So; </span> "x² + 9x − 22" ; factors into " (x−2)(x + 11)" ;
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We have: (x−2)(x + 11) = 0 ;

So: x − 2 = 0 ;

Add "2" to each side of the equation;

x − 2 + 2 = 0 + 2 ;

x = 2 ;
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x + 11 = 0 ;

Subtract "11" from each side of the equation;

x + 11 − 11 = 0 − 11 ;

x = -11 ;
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Answer: x = 2 ; -11 .
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6 0

3 years ago

Please help me answer this question

ratelena [41]

By the definition of the hyperbolic function tanh x, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$