The question is incorrect
the correct question is
A local citizen wants to fence a rectangular community garden. The length of the garden should be at least 110 ft,and the distance around should be no more than 380 ft. Write a system of inequality that model the possible dimensions of he garden. Graph the system to show all possible solutionslet
x---------------> t<span>he length of the garden
</span>y---------------> the wide of the garden
we know that
x>=110
2x+2y <=380---------------> x+y <= 190
Part A) <span>Write a system of inequality that model the possible dimensions of he garden
</span>
the answer part A) is
x>=110
x+y <= 190
Part B) <span>Graph the system to show all possible solutions
using a graph tool
see the attached figure
the solution is the triangle show in the figure
</span><span>the possible solutions of y (wide) would be between 0 and 80 ft
</span>the possible solutions of x (length) would be between 110 ft and 190 ft
Answer:
x = 3
, y = 5
Step-by-step explanation:
Solve the following system:
{3 y - 7 x = -6 | (equation 1)
3 y - 3 x = 6 | (equation 2)
Subtract 3/7 × (equation 1) from equation 2:
{-(7 x) + 3 y = -6 | (equation 1)
0 x+(12 y)/7 = 60/7 | (equation 2)
Multiply equation 2 by 7/12:
{-(7 x) + 3 y = -6 | (equation 1)
0 x+y = 5 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{-(7 x)+0 y = -21 | (equation 1)
0 x+y = 5 | (equation 2)
Divide equation 1 by -7:
{x+0 y = 3 | (equation 1)
0 x+y = 5 | (equation 2)
Collect results:
Answer: {x = 3
, y = 5
Hello
DEF and IKL , equilateral =>
DE = 5x-12 = 3x-4
5x-3x= -4+12
2x= 8
x=4
DE = 5x-12 = 20-12 = 8
KL = 3x+24 = 10x+3
24 -3 = 10x-3x
21 = 7x
x= 21/7 = 3
KJ = 10x+3 = 30+3 = 33
Both of these variables represent a common measure used in chemistry.
The amount of material/volume is the material’s concentration.
The rate is the reaction is increase by altering the concentration.
Answer:
There are 60 permutations that can be formed from the first five letters of the alphabet.
Step-by-step explanation:
The number of three letter permutations that can be formed from the first five letters of the alphabet is
.


= 60
Hence, there are 60 permutations that can be formed from the first five letters of the alphabet.