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Neko [114]
2 years ago
10

Sin10°-cos10° product and evaluate​

Mathematics
2 answers:
Elena-2011 [213]2 years ago
8 0

\\ \sf\longmapsto sin10°-cos10°

\\ \sf\longmapsto sin(90-10°)-cos10°

  • sin(90-A)=cosA

\\ \sf\longmapsto cos10-cos10

\\ \sf\longmapsto 0

Montano1993 [528]2 years ago
6 0

Question should be sin 20 cos 10 + cos 20 sin 10

remember sin (a+b) = sin a cos b + cos a sin b ?

sin 20 cos 10 + cos 20 sin 10

= sin (20+10)

= sin 30

= 1/2

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aleksandrvk [35]
Let the numbers be x and y.
x*y=HCF*LCM=6*60=360
thus
y=360/x
next we find the list of combinations of x and y and test if they satisfy the conditions above:
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out of the above, only (6,60) and (12,30) satisfy both conditions. Thus our answer is:
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3 years ago
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Anna [14]

Given:

The slope of the line is -3.

The line passes through the point (2,-2).

To find:

The point-slope form of the line.

Solution:

Point slope form: If a line passes through the point (x_1,y_1) with slope m, then the point-slope form of the line is:

y-y_1=m(x-x_1)

The slope of the line is -3 and it passes through the point (2,-2). So, the point-slope form of the line is:

y-(-2)=-3(x-2)

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viva [34]
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First, you need to use the distributive property on the right to get -30-5x=-4x-30-24x

Then, you can add like terms to get -30-5x=-30-28x

Then, you can add 30 to both sides and add 5x to both sides to get 0=-23x

Finally, you divide both sides by -23 to get 0=x
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garri49 [273]
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