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Tju [1.3M]
3 years ago
11

1 1. You can work at most 20 hours next week. You need to earn at least $92 to cover you weekly expenses. Your dog- walking job

pays $7.50 per hour and your job as a car wash attendant pays $6 per hour. Write a system of linear inequalities to model the situation. 2. Marsha is buying plants and soil for her garden. The soil cost $4 per bag, and the plants cost $10 each. She wants to buy at least 5 plants and can spend no more than $100. Write a system of linear inequalities to model the situation.
Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0
<span>Let x be the number of hours spent in dog-walking Let y be the number of hours spend in car washing. The maximum number of hours at work in a week is 20. Therefore x + y <=20 Salary for dog-walking job =$7.50/ hour Salary for car washing job=$6/ hour Total salary in a week earned through dog-walking job =7.50x Total salary in a week earned through car washing job=6y Least amount to be earned in a week =$92 Therefore, 7.50x +6y>=92 The required inequalities are x+y<=20; 7.50x+6y>=92 2. Let x be the number of soil bags Let y be the number of plants Cost per soil bag = $4 Cost per plant =$10 Minimum number of plants she wants to buy =5 Therefore, y>=5 Maximum amount she can spent =$100 Therefore 4x+10y<=100 The required inequalities are y>=5; 4x+10y<=100</span>
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olya-2409 [2.1K]

Answer:

Perimeter \sqrt{26}+\sqrt{5}+\sqrt{10}+\sqrt{17} units.  Area 12 square units.

Step-by-step explanation:

Perimeter: total distance around the figure.

Distance Formula:  the distance between points \left(x_1,y_1\right) \text{ and } \left(x_2,y_2\right) is

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

AB=\sqrt{(6-1)^2+(2-1)^2}=\sqrt{25+1}=\sqrt{26}

BC=\sqrt{(5-6)^2+(4-2)^2}=\sqrt{1+4}=\sqrt{5}CD=\sqrt{(2-5)^2+(5-4)^2}=\sqrt{9+1}=\sqrt{10}DA=\sqrt{(1-2)^2+(1-5)^2}=\sqrt{1+16}=\sqrt{17}

The perimeter is the sum of all those segment lengths.

One way to find the area of the figure is to surround it with a rectangle, insert some lines so that the areas you do not want can be found and subtracted from the rectangle's area.  (See attached image.)

The area of the large rectangle around the figure is 5 x 4 = 20 square units.

The triangles have areas 1/2 (base) (height):

A. (1/2)(1)(4) = 2 square units

B. (1/2)(3)(1) = 1.5 square units

D. (1/2)(1)(2) = 1 square unit

E. (1/2)(5)(1) = 2.5 square units

Square C.  (1)(1) = 1 square unit

Total of all the area you don't want to include:

2 + 1.5 + 1 + 2.5 + 1 = 8 square units

Subtract 8 from the surrounding rectangle's area of 20, and you get the area of the figure is 20 - 8 = 12 square units.

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3 years ago
Is this the right answer?
Ne4ueva [31]
Yes your answer is solved correctly
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Was increased by 1 inch, the new measure of each side would be 4 inches.
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