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2 years ago

Im confused on this: Evaluate: 4+8÷2x (6-3)

Mathematics

2 answers:

VashaNatasha [74]2 years ago

5 0

Answer:

12x+4

Step-by-step explanation:

We can solve this by using PEMDAS (parentheses exponents multiplication division addition subtraction) to solve this in the correct order:

4+8÷2x (6-3)

So first we solve (6-3) since it’s in parentheses:

4+8÷2x (3)

Now we multiply 3 times 8/2x:

4+8/2x(3)

4+12x

(Put in order)

12x+4

And that^ is the answer because we cannot simplify any further!

Hope this helps :)

Radda [10]2 years ago

3 0

Answer:

hello there

ok so the answer is 4 + $\frac{4}{3x}$

Step-by-step explanation:

hope this helps!

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Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$

The minimum initial velocity needed for the ball to clear the fence is $125.4\ \text{m/s}$

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Answer:

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Step-by-step explanation:

Solve both equations for y to make it easier to compare them.

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Answer:

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Step-by-step explanation:

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