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3 years ago

1. Are the following triangles similar? Justify your answer.

Mathematics

1 answer:

DerKrebs [107]3 years ago

5 0

Answer:

no they are not similar. this is because figure MCD had no corresponding sides to figure NLO. The two figures are not congruent or similar

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An experiment consists of randomly selecting a marble from a bag, keeping it, and then selecting another marble. The bag contain

beks73 [17]

Answer:

13.33%

Step-by-step explanation:

First we need to find the total number of marbles

4 blue marbles+ 3 green marbles+ 7 red marbles+ 1 yellow marble= 15

The probability of a red marble = number of red marbles over the total marbles

P(red) = red/total = 7/15

We keep the marble. There are now 6 red marbles

4 blue marbles+ 3 green marbles+ 6 red marbles+ 1 yellow marble= 14

We have 14 marbles in the bag

The probability of a blue marble = number of blue marbles over the total marbles

P(blue) = blue/total = 4/14 = 2/7

Then we multiply the probabilities together

P(red,blue0 = 7/15 * 2/7 = 2/15 =.13333333 = 13.33%

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3 years ago

-1/2 + 4/9

stira [4]

Answer:

-1/18

Step-by-step explanation:

First, you have to change both fractions to have like denominators. The LCM of 2 and 9 is 18.

Second, you have to multiply -1/2 by 9/9 to get a denominator of 18. -1/2 x 9/9 is - 9/18.

Third, you have to multiply 4/9 by 2/2 to get a denominator of 18. 4/9 x 2/2 = 8/18.

Fourth, -9/18 + 8/18 = -1/18

Hope this helps!

4 0

3 years ago

Neil wants to buy some video games over the Internet. Each game costs $25.01 and has a shipping cost of $9.98 per order. If Neil

ozzi

The answer to the question is <span> 9.98 + 25.01p ≤ 60</span>

5 0

3 years ago

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A study indicates that 62% of students have have a laptop. You randomly sample 8 students. Find the probability that between 4 a

Scrat [10]

Answer:

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A study indicates that 62% of students have have a laptop.

This means that $n = 0.62$

You randomly sample 8 students.

This means that $n = 8$

Find the probability that between 4 and 6 (including endpoints) have a laptop.

$P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{8,4}.(0.62)^{4}.(0.38)^{4} = 0.2157$

$P(X = 5) = C_{8,5}.(0.62)^{5}.(0.38)^{3} = 0.2815$

$P(X = 6) = C_{8,6}.(0.62)^{6}.(0.38)^{2} = 0.2297$

$P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.2157 + 0.2815 + 0.2297 = 0.7269$

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

3 0

3 years ago

Mike sees 3 more fish than Chris. Chris sees 6 fish. How many fish does Mike see? It says use comparison bars. Thanks

Katen [24]

Chris sees 6 fish.

Mike sees 3 more fish than Chris.

6 + 3 = 9

So on your bar, you have Chris's number of fish he saw, 6, and you have 3 being added to that on Mike's bar.

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3 years ago

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