-4 is your answer hope this helps
The radius of a circle is
always half of the diameter of the circle. In this case, the diameter is
, meaning that when we halve
, we will get our radius. Therefore, the radius of the circle is
. Hope this has helped you understand and have a great day!
Solving the complex number, we get the value of the missing value that is ‘a’ = -6
We have been given the expression as
|a – i| = √37 (1)
Which is an expression of complex number. The general expression of complex number is given as
z = x + iy
where x is the real part and iy is the imaginary part
To find the modulus value, the formula is given by,
|z| = |x + iy|
|z| = √[(real part)2 + (imaginary part)2]
|z| = √(x2 + y2)
According to the question, |z| = √37 (2)
Equating equation (1) and (2), we get
√(a2 + 1) = √37
(a2 + 1) = 37
a2 = 37 – 1
a2 = 36
a = √36
a = ±6
Now value of a can be 6 or -6. We have been given that the modulus is in third quadrant.
Hence the value will be negative. Therefore, the missing value will be -6.
Learn more about complex number here : brainly.com/question/5564133
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Distributive property was the first property used in STEP 1, where -4 was distributed to -3x+ 2 resulting in the equation in STEP 1. Next in STEP 2, commutative property of addition no matter how 12x and 6x are arranged, when you add them together the result will be the same.
*Take note that 12x and 6x are put together because they are like terms.
For Steps 3 and 4, you will see that the addition property of equality was used in STEP 3. To keep the equation equal, you will add the same number on both sides.
STEP 4 uses Division property of Equality. Like Step 3, to keep both sides of the equation equal, you must divide both sides with the same number. It keeps the statement true by doing so.
STEP 4 and 5 uses transitive property if you examine both as a whole.
Transitive property assumes that if a = b and b = c, then a = c
If 18/18 (a) = 1 (b), and x (c) = 18/18(a) then, x (c) = 1 (b).
Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes
so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so
x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero
x³=0
x=0
x-∛3=0
x=∛3
x²+x∛3+∛9=0 has no solution
x+∛3=0
x=-∛3
x²-x∛3+∛9=0 has no solution
so the solutions are
x=-∛3, 0, ∛3
