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4 years ago

15

Match each quadratic equation with its solution set. arrowRight arrowRight arrowRight arrowRight

2 answers:

quester [9]4 years ago

8 0

Answer:

1 is 7 2 is -3 3 is -2 4 is 3

Step-by-step explanation:

Need points

vova2212 [387]4 years ago

7 0

Answer:

Step-by-step explanation:

For this case we solve each of the equations:

Adding 32 to both sides of the equation:

Dividing between 2 on both sides of the equation:

Applying square root to eliminate the exponent:

Second equation:

Adding 100 to both sides of the equation:

Dividing between 4 on both sides of the equation:

Applying square root to eliminate the exponent:

Third equation:

Adding 55 to both sides of the equation:

Applying square root to eliminate the exponent:

Fourth equation:

Adding 140 to both sides of the equation:

Applying square root to eliminate the exponent:

Fifth equation:

Adding 18 to both sides of the equation:

2x ^ 2 = 18

Dividing between 2 on both sides of the equation:

Applying square root to eliminate the exponent:

Answer:

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A publication released the results of a study of the evolution of a certain mineral in the Earth's crust. Researchers estimate

san4es73 [151]

Answer:

a) $E(A)=\frac{1+6}{2}=3.5 ppm$

b) $P(2.875$

c) $P(X$

Step-by-step explanation:

If we work with the limits defined from 5 to 10 then part b and c from this question not makes sense. If we work with the limits 1 and 6 all the parts for the question makes sense because if we work with 5 and 10 the only thing that we can find is the expected value $E(A) = \frac{5+10}{2}= 7.5$

Assuming the following correct question : "A publication released the results of a study of the evolution of a certain mineral in the Earth's crust. Researchers estimate that the trace amount of this mineral x in reservoirs follows a uniform distribution ranging between 1 and 6 parts per million"

Solution to the problem

Let A the random variable that represent " amount of the mineral x ". And we know that the distribution of A is given by:

$A\sim Uniform(1 ,6)$

Part a

For this uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(A)=\frac{1+6}{2}=3.5 ppm$

Part b

For this case we can use the cumulative distribution function for the uniform distribution given by:

$F(X=x)= \frac{x-a}{b-a} = \frac{x}{6-1} =\frac{x-1}{5} , 1 \leq X \leq 6$

And we want this probability: $P(2.875$ Part c

For this case we want this probability:

$P(X$

3 0

3 years ago

A spherical weather balloon is being inflated. The radius of the balloon is increasing at the rate of 7 cm/s. Express the surfac

Tcecarenko [31]

R(t) = 6t

<span>putting into the formula </span>

<span>V = (4/3) pi * r^3 </span>

<span>V(t) = (4/3) pi * (6t)^3 </span>
<span> </span>
<span>V(t) = (4/3) pi * 216 t^3

Multiply the 4/3 by the 216 and </span>

<span>V(t) = 288 * pi * t^3</span>

7 0

3 years ago

Read 2 more answers

This relation is an inverse variation {(-1,8),(4,-2),(-2,4)} what equation represents this relation?

swat32

ANSWER

$y = - \frac{8}{x}$

EXPLANATION

An inverse variation equation is of the form:

$y = \frac{k}{x}$

We plug in the point (-1,8).

$8= \frac{k}{ - 1}$

This implies that k=-8

Therefore the inverse variation equation is :

$y = - \frac{8}{x}$

8 0

4 years ago

Solve: (3√8x - 2 )= 4<br> To solve this equation, first<br> _____both sides.<br> x =_____

PIT_PIT [208]

Answer:

Add 2 to each side

x=1/2

Step-by-step explanation:

(3√8x - 2 )= 4

Add 2 to each side

(3√8x - 2 +2= 4+2

3√8x = 6

Divide each side by 3

3/3√8x = 6/3

√8x = 2

Square each side

(√8x)^2 = 2^2

8x = 4

Divide each side by8

8x/8 = 4/8

x = 1/2

5 0

3 years ago

The results of rolling a 6-sided die 120 times are given in the table below.

Bas_tet [7]

Step-by-step explanation:

According to the results of rolling a 6-sided die 120 times, we have:

Rolling a 2:

Experimental = 15/120 = 1/8 = 0.125 = 12.5%

Theoretical = 20/120 = 1/6 = 0.1667 = 16.67%

Rolling a 1:

Experimental = 18/120 = 3/20 = 0.15 = 15%

Theoretical = 20/120 = 1/6 = 0.1667 = 16.67%

Rolling a 1 or 6:

Experimental = 18/120 + 20/120 = 38/120 = 19/60= 0.3167 = 31.67%

Theoretical = 20/120 + 20/120 = 40/120 = 1/3 = 0.3333 = 33.33%

Step-by-step explanation:

1. First of all, let's recall what is the difference between experimental and theoretical probability of an event.

The experimental probability is the result of an experiment, and the theoretical probability is based on the mathematical model developed in the theory of probability. In simple words, the most important difference is that the experimental probability is based on what actually happens and the theoretical probability on what is expected to happen.

The accuracy of the results of the experiments depends directly on the sample size of the experiment and the accuracy is greater when the sample size is larger.

For this particular event the theoretical probability is the same for rolling each number of the die, 1/6 or 16.67%

Now, let's complete the answer this way:

Rolling a 2:

Experimental = 15/120 = 1/8 = 0.125 = 12.5%

Theoretical = 20/120 = 1/6 = 0.1667 = 16.67%

Rolling a 1:

Experimental = 18/120 = 3/20 = 0.15 = 15%

Theoretical = 20/120 = 1/6 = 0.1667 = 16.67%

Rolling a 1 or 6:

Experimental = 18/120 + 20/120 = 38/120 = 19/60= 0.3167 = 31.67%

Theoretical = 20/120 + 20/120 = 40/120 = 1/3 = 0.3333 = 33.33%

5 0

3 years ago