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malfutka [58]
2 years ago
14

0.22y × 0.06 =please help me​

Mathematics
1 answer:
irakobra [83]2 years ago
7 0

Answer:

0.0132y :DDDDDDDDDD

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Which number line shows the solution to this compound inequality?
serious [3.7K]

Answer:

The explanation is on top x=10

3 0
3 years ago
V=n/t+10<br> solve for n
AnnZ [28]

Answer:

Lets isolate

v-10=n/t

negate the right side

t(v-10)= n

8 0
2 years ago
Square A has a side length of (2x - 7) and Square B has a side length (-4x + 18). How much bigger is the perimeter of Square B t
stich3 [128]

Answer: 100 - 24x

Step-by-step explanation:

The formula for calculating the perimeter of a square is given by :

P = 4l , where l is the length of the side.

Perimeter of square A will be

P = 4 ( 2x - 7 )

P = 8x - 28

Perimeter of square B will be ;

P = 4 ( -4x + 18 )

P = - 16x + 72

Perimeter of square B - Perimeter of square A implies

-16x + 72 - ( 8x - 28 )

-16x + 72 - 8x + 28

collecting the like terms

-16x - 8x + 72 + 28

-24x + 100

⇒ 100 - 24x

3 0
3 years ago
17 points)Which figures are similar to the one without a letter please explain I’m a little confused.....?plz help
erik [133]

Answer:

The letter  D

Step-by-step explanation:

because of the present in the top-left corner has no letter and it maches with the present that has no color and that is the letter D    XD  thanks brainleiiest plz

8 0
2 years ago
Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a
Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = \frac{1}{6}

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

E(X)=\sum x\cdot P(X=x)

Compute the expected monetary value of a single roll as follows:

E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17

Thus, the expected monetary value of a single roll is $1.17.

7 0
3 years ago
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