Answer:16
Step-by-step explanation:
base times height of both figures then add
S+m+l=28
4s+2m+l=58
6s+5m+4l=135
Eliminate the variable l from the first 2 equations
s+m+l=28
-4s-2m-l=-58
-3s-m=-30
Elminiate the variable l from the last 2 equations
6s+5m+4l=135
-16s-8m-4l=-232
-10s-3m=-97
Now solve for s and m using the 2 equations without l
-3s-m=-30
-10s-3m=-97
9s+3m=90
-10s-3m=-97
-s=-7
s=7
Then plug in s into one of the equations without l
-3(7)-m=-30
-21-m=-30
-m=-9
m=9
Now plus in s and m into one of the original 3 equations
(7)+(9)+l=28
16+l=28
l=12
Final answer:
Small=$7
Medium=$9
Large=$12
I know it only asks for large but I wanted to show you how to find them all for future reference. :)
Try this explanation:
1. if to re-write the given function as:

then it is possible to define its range:
2)
![\lim_{x \to+ \infty}[1- \frac{C}{e^x+C}]=1; \\ \lim_{x \to- \infty}[1- \frac{C}{e^x+C}]=0](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%2B%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D1%3B%20%20%5C%5C%20%5Clim_%7Bx%20%5Cto-%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D0)
answer: (0;1)
The answer is C.
(0, 3)
y = x + 3
3 = 0 + 3
3 = 3
(1, 4)
y = x + 3
4 = 1 + 3
4 = 4
(2, 5)
y = x + 3
5 = 2 + 3
5 = 5
You take the amount paid and divide it by the amount of cheese. So 10.50 divided by 2.5 equals 4.2 and 12.60 divided by 3 equals 4.2 meaning that one pound of cheese costs $4.20