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Oksi-84 [34.3K]
3 years ago
13

The operating costs for each machine for one day have an unknown distribution with mean 1610 and standard deviation 136 dollars.

A sample, with size n=45, was randomly drawn from the population. Using the Central Limit Theorem for Means, what is the standard deviation for the sample mean distribution? Select the correct answer below: 3.02 20.27 25.34 30.41 34.47 136.00
Mathematics
1 answer:
BabaBlast [244]3 years ago
3 0

Answer:

20.27

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

Using the Central Limit Theorem for Means, what is the standard deviation for the sample mean distribution?

This is s when \sigma = 136, n = 45. So

s = \frac{136}{\sqrt{45}} = 20.27

So the correct answer is:

20.27

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Mr. Velasquez built a playground. It has one section with a slide and another section with a swing set. A pathway connects the t
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Answer:

A_1 = 24m^2 -- Swing set

A_2 = 16m^2 -- Slide

A_3 = 5m^2 --- Pathway

Step-by-step explanation:

Missing part of the question:

Fill in the table above to show the area of each section (see attachment for table)

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3 years ago
Triangle QRS has medians QU, RV, and ST. If the measure of segment RW is 18 meters, what is the length of segment RV?
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The attached figure shows the medians and centroid.

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RV = \frac{3}{2}.18

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The median RV measures 27 meters.

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