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Kryger [21]
3 years ago
9

Mrs. Van Sant is using 1 scoop of lemonade mix for every 2 liters of water to make some lemonade. She is having a party and want

s to make 12 liters of lemonade. How much lemonade mix should she use?
Mathematics
2 answers:
oee [108]3 years ago
5 0
6 scoops of lemonade mix
vichka [17]3 years ago
5 0
It would be six (6) litres
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5. A company sells small, colored binder clips in packages of 20 and offers a money-back guarantee if two or more of the clips a
SOVA2 [1]

Answer:

a) Binomial.

b) n=20, p=0.01, k≥2

The probability hat a package sold will be refunded is P=0.0169.

Step-by-step explanation:

a) We know that

  • the defective probability is constant and independent.
  • the sample size is bigger than one subject.

The most appropiate distribution to represent this random variable is the binomial.

b) The parameters are:

  • Sample size (amount of clips in the package): n=20
  • Probability of defective clips: p=0.01.
  • number of defective clips that trigger the money-back guarantee: k≥2

The probability of the package being refunded can be calculated as:

P(x\geq2)=1-(P(x=0)+P(x=1))\\\\\\P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}\\\\\\P(x=0) = \dbinom{20}{0} p^{0}q^{20}=1*1*0.8179=0.8179\\\\\\P(x=1) = \dbinom{20}{1} p^{1}q^{19}=20*0.01*0.8262=0.1652\\\\\\P(x\geq2)=1-(0.8179+0.1652)=1-0.9831=0.0169

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3 years ago
Please ignore the messy laptop..it’s not mine
vovangra [49]

answers

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5 0
2 years ago
Solve for b.<br> 39 = 28 - 6
prohojiy [21]

Answer:

39=22

28-6 equal to 22 so 39= 22

7 0
3 years ago
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grigory [225]

Answer:

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Step-by-step explanation:

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3 years ago
Let log_(b)A=3; log_(b)C=2; log_(b)D=5 what is the value of log_(b)((A^(5)C^(2))/(D^(6)))
Colt1911 [192]

Answer:

-11

Step-by-step explanation:

Given

\log_bA=3\\ \\\log_bC=2\\ \\\log_bD=5

Use properties:

\log_b(A\cdot C)=\log_bA+\log_bC\\ \\\log_b\dfrac{A}{C}=\log_bA-\log_bC\\ \\\log_bA^k=k\log_bA

Thus,

\log_b\dfrac{A^5\cdot C^2}{D^6}\\ \\=\log_b(A^5\cdot C^2)-\log_bD^6\\ \\=\log_bA^5+\log_bC^2-\log_bD^6\\ \\=5\log_bA+2\log_bC-6\log_bD\\ \\=5\cdot 3+2\cdot 2-6\cdot 5\\ \\=15+4-30\\ \\=-11

3 0
3 years ago
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