Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
As the front approaches, you will have a storm.
I hope this helps!
Answer:
The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month
P(X≥ 2800) = P(Z₁≥1.5) = 0.0768
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Mean of the Population (μ) = 2500 gallons
Standard deviation of the population (σ) =200 gallons
Let 'X' be a random variable in Normal distribution
Given X = 2800
<u><em>Step(ii):-</em></u>
The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month
P(X≥ 2800) = P(Z₁≥1.5)
= 0.5 - A(Z₁)
= 0.5 - A(1.5)
= 0.5 -0.4232 ( from normal table)
= 0.0768
<u><em>Conclusion</em></u>:-
The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month
P(X≥ 2800) = P(Z₁≥1.5) = 0.0768
Answer:
It goes 18 cm every second:
18 x 4 = 72 cm
The bridge is 72 cm long.
Hope this helps!
The answer of this equation is a^n=9(-1/4) (n+ 1)
