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2 years ago

The mean vitamin C level for 20 dogs was 7.6 milligrams per liter, with a standard deviation of 2.1 milligrams per liter.

Mathematics

1 answer:

SpyIntel [72]2 years ago

5 0

Answer: The mean increases.

Step-by-step explanation:

The value of 0.9 mg/L is very low compared to a means of 7.6 mg/L with a standard deviation of 2.1 mg/L. It seems as though it is an outlier that is suffiently different from the others, and probably should be dropped from the data set. That would do 2 things: 1) the stabdard deviation will likely decrease, indicating a more confident data set, and 2) the mean vitamin C level will increase.

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stepan [7]

Answer:

y = 4x-3

Step-by-step explanation:

First we need to determine the slope

Using two points on the line (0,-3) (1,1)

Using the slope formula

m = (y2-y1) /(x2-x1)

= (1- -3)/(1-0)

(1+3)/ (1-0)

We know the y intercept, -3

y = mx+b where m is the slope and b is the y intercept

y = 4x-3

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If given f(x) = –4x – 2 and g(x) = 2x, what is (f · g)(x)?

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4 years ago

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54.5*17=926.5

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3 years ago

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3 years ago

Train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train tra

stepan [7]

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor =?

Solution:

The speed of the train A = $\frac{Distance}{time}$

The speed of train A = $\frac{175}{4}$

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5 miles per hours

Train A travels faster

$Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}$

$rate = \frac{43.75}{43.5}$

rate =1.01

7 0

3 years ago