IFKDIKDKSBWKANDBSKSLFBAKKENSS
Given equations are;<span>
2a + 3b = -1 ..................equation 1
3a + 5b = -2 ....................equation 2</span>
Now multiply equation 1 with (-3)
The equation will be;
-6a -9b = 3 …………………..equation 3
Now multiply equation 2 with (2)
The equation will be;
6a + 10b = -4 ……………..equation 4
Now add equation 3 and equation 4
-6a – 9b = 3
<span>6a + 10b = -4</span>
<span>------------------------------</span>
0a + b = -1
b = -1
Now put the value of b in equation 1
2a + 3(-1) = -1
2a -3 = -1
2a = -1+3
2a = 2
a=1
Thus the solution is (a,b) = (1,-1)
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I think the answer would be x= 4/7 y = +-16/7
Answer:
tan2θ = 4√2/7
Step-by-step explanation:
Given sin theta=1/3 and 0 < theta< π/+
Required
tan 2 theta
tan2 theta = 2tanθ/1-tan²θ
Get tan θ
sinθ = opp/hyp
adj = √3²-1²²
adj = √9-1
adj = √8
tanθ = opp/adj = 1/2√2
tan2 theta = 2(1/2√2/1-(1/2√2)²
tan2θ = 1/√2/1-1/8
tan2θ = 1/√2/7/8
tan2θ = 8/7√2
Rationalize
tan2θ = 8√2/14
tan2θ = 4√2/7
