Answer: the domain of f/g is every real number except 1 which can be conventionally expressed as {(x,y): <em>x</em> ∈ R, x ≠ 1} OR (-∞ ≤ x < 1) ∩ (1< x ≤ ∞) OR x ∈ R; x ≠ 1.
Step-by-step explanation:
since f(x) = x + 4 and g(x) = x - 1
then f/g = x + 4/x - 1
the denominator of a function cannot be zero since a fraction with a denominator of zero is undefined.
∴ x - 1 ≠ 0
the value of x when g(x) = 0 is
x - 1 = 0
x = 1
∴ x ≠ 1
Therefore the domain of f/g is every real number except 1 which can be conventionally expressed as {(x,y): <em>x</em> ∈ R, x ≠ 1} OR (-∞ ≤ x < 1) ∩ (1< x ≤ ∞) OR x ∈ R; x ≠ 1.
Answer:
A
Step-by-step explanation:
Domain the "input" to the function, range is the "output" of the function.
It would be d if the markup was that high
You start with the basic y=x^2.
That’s the parabola with a vertex at (0,0), opening up, etc.
The transformation aspect is the “+7” portion. This “+7” shifts the entire graph of y=x^2 up by 7 units.
The vertex is now (0,7), it still opens up, etc.
It’s kind of a silly question for your teacher to ask when the graph given only goes up to 6.
