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sdas [7]
3 years ago
15

Which equation represents a linear function? Equation 1: y^3 = 2x +1 Equation 2: y= 3x +1 Equation 3: y= 5x^2 - 1 Equation 4: y=

4x^4 -1
Mathematics
1 answer:
Yuri [45]3 years ago
8 0
the second equation is linear
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There is 3 4 of an apple pie left from dinner. Tomorrow, Victor plans to eat 1 4 of the pie that was left. Enter how much of the
lora16 [44]

Answer:

3/16

Step-by-step explanation:

Let the size of the whole apple be T

Given that 3/4 of the apple is left, it means the size left

= 3T/4

Since Victor plans to eat 1/4 of the pie that was left, this amounts to

1/4 * 3T/4

= 3T/16

This means that Victor will eat 3/16 of the whole pie tomorrow

5 0
3 years ago
I need help on this math problem.
OLEGan [10]

B: (0, a)

C should have the same y value as B

D: (a,0)

C should have the same x value as D


So point C is (a,a)

Since point A is on the origin, its point is (0,0)


You use the slope formula and plug in point A and C:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{a-0}{a-0}

m=\frac{a}{a}

m = 1


So the value that belongs in the green box is 1


6 0
3 years ago
Which expressions are equivalent to 7•7•7•7•7•7
Alex

Answer:7^6

Step-by-step explanation:

7 0
3 years ago
Help meeeeeeeee answer these questions or correct them your like my human checker because calculators to check get boring
IRISSAK [1]
4 is 16.3, I don't know 5 or 6, 7 is 176, I don't know 8 or 9, 10 is 8.1, I don't know 11, and 12 is 48.
(I used a calculator, lol)
4 0
3 years ago
At a production process, the produced items are tested for defects. A defective unit is classified as such with probability 0.9,
Snezhnost [94]

Answer:

We use Baye's theorem:  P(A)P(B|A) = P(B)P(A|B)

with (A) being defective and

(B) marked as defective

we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)

Since  P(A) = 0.1 and P(B|A)=0.9,

P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9

and

P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15

put these values in eq(2)

P(B) = (0.1 × 0.9) + (0.9 × 0.15)

       = 0.225 put this in eq(1) and solve for P(B)

P(B) = 0.4

6 0
3 years ago
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