Answer: 3.712 hours or more
Step-by-step explanation:
Let X be the random variable that denotes the time required to complete a product.
X is normally distributed.

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.
Then, 
![P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]](https://tex.z-dn.net/?f=P%28z%3E%5Cdfrac%7Bx-3.2%7D%7B%5Csigma%7D%29%3D0.10%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D)
As,
[By z-table]
Then,

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.
The average number of viewers over the two week is D. 4.85 x 10^5.
<h3>How to calculate the value?</h3>
It should be noted that the scientific notation simply has to do with writing of numbers that are either too large or too small. This will be illustrated thus:
In this case, the TV show had 5.6 x 10^5 viewers in the first week and 4.1 x 10^5 viewers in the second week.
Therefore, the average number of viewers over the two weeks will be:
= (5.6 × 10^5) + (4.1 × 10^5) / 2
= 4.85 × 10^5
Note that we had to divide by 2 since it's average.
Learn more about notation on:
brainly.com/question/5756316
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