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3 years ago

Change 3 radians to degree measures

Mathematics

2 answers:

uysha [10]3 years ago

7 0

<span>π radians =180∘</span>

1 radian = tex] \frac{180°}{ \pi} [/tex]π

3 radians = $\frac{540°}{ \pi}$

ivolga24 [154]3 years ago

7 0

Multiply the radians by 180pi and that will your answer

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Step-by-step explanation:

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IgorC [24]

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yes , 33^2 + 56^2 = 65^2 and obtuse

Step-by-step explanation:

<h2><u>Question 3</u></h2>

make use of the Pythagoras theorem

which is :

c^2 = a^2 + b^2

where c is the hypotenuse.

now put the values in the equation

65^2 = 56^2 + 33 ^2

the answer is :

<u></u>

<h2><u>Question 4</u></h2>

<u />

note if :

c^2 = a^2 + b^2 ----------- right

c^2 < a^2 + b^2------------ acute

c^2 > a^2 + b^2------------- obtuse

hence :

16 + 30 > 38

therefore its : <u>obtuse </u>

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .