It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.
The simplest polynomial with these characteristics would be
but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with
which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:
I think it should be 25 blocks east
4X-12+2Xe5
6Xe5-12 IS THE ANSWER
The area of a rectangle is length*width.
The length of this 3x and the width is 2x-3. This means that, to find the area, you need to multiply 3x and 2x-3.
Start by writing out this equation:
A=l*w
Then, plug in your given values:
A= 3x*2x-3 (you can also write it as A= 3*x*2*x-3)
Then, following the order of operations, you start by multiplying. This makes your equation become A = 6x^2 -3. (^2 means squared). It turns into this because 3 * 2 is 6 and x * x is x^2 and you still haven’t used the 3 yet.
After this, there is nothing more that you can do to simplify the equation. Therefore, the area is 6x^2 - 3.
I hope this helped!
