Answer is in a photo. I can only upload it to a file hosting service. link below!
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F(x) = 2^x; h(x) = x^3 + x + 8
Table
x f(x) = 2^x h(x) = x^3 + x + 8
0 2^0 = 1 0 + 0 + 8 = 8
1 2^1 = 2 1^3 + 1 + 8 = 10
2 2^2 = 4 2^3 + 2 + 8 = 8 + 2 + 8 = 18
3 2^3 = 8 3^3 + 3 + 8 = 27 + 3 + 8 = 38
4 2^2 = 16 4^3 + 4 + 8 = 76
10 2^10 = 1024 10^3 +10 + 8 = 1018
9 2^9 = 512 9^3 + 9 + 8 = 729 + 9 + 8 = 746
Answer: an approximate value of 10
Answer: The Answer is "less than"
Step-by-step explanation:
To find the sum of a series, you find the difference between the first and last term, multiply that by the number of terms, then divide by 2.
For the even numbers, 2 is the first term and 200 is the 100th term (because 2+(100-1)2 is equal to 200). So, (100(2+202)/2 = 10100.
For the odd numbers, 1 is the first term and 201 is the 101th term (because 1+(101-1)2 is equal to 201). So, (101(1+202))/2 = 10251.5.
10100<10251.5 so the sum of the first 100 even numbers is less than the sum of the first odd 101 numbers.
Well the first equation has a variable in it while the other one doesn't also the first expression if set equal to 0 is -2 while the other one is 5
