Answer:
a. Class width=4
b.
Class midpoints
46.5
50.5
54.5
58.5
62.5
66.5
70.5
c.
Class boundaries
44.5-48.5
48.5-52.5
52.5-56.5
57.5-60.5
60.5-64.5
64.5-68.5
68.5-72.5
Step-by-step explanation:
There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,
Class
Interval frequency
45-48 1
49-52 3
53-56 5
57-60 11
61-64 7
65-68 7
69-72 1
a)
Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.
Class width=49-45=4
b)
The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

Class
Interval Midpoints
45-48 
49-52 
53-56 
57-60 
61-64 
65-68 
69-72 
c)
Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.
Class
Interval Class boundary
45-48 44.5-48.5
49-52 48.5-52.5
53-56 52.5-56.5
57-60 56.5-60.5
61-64 60.5-64.5
65-68 64.5-68.5
69-72 68.5-72.5
Step-by-step explanation:
Can you attach the questions please? Thanks
Answer: n = -14
Step-by-step explanation:
n/2 = -7
Multiply by 2 on each side to get the variable alone.
n = -14
Answer: -5x + 2y -9 = 0
Step-by-step explanation:
1. Move constant to the left and change its sign
2. Change the signs on both sides of the equation
The two correct relationships are:

<h3>What is a right-angled triangle?</h3>
The triangle shown is a right-angled triangle
Considering <

Considering <

Comparing <
and <
, the true statements are:

Learn more on trigonometry here: brainly.com/question/20519838