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frutty [35]
3 years ago
15

Ben uses a compass and a straightedge to bisect angle PQR, as shown below: The figure shows two rays QP and QR having a common e

nd point Q. An arc drawn from Q cuts the ray QP at A and the ray QR at B. Two small arcs intersect between the lines QP and QR. The point of intersection of the arcs is labeled S. The points Q, S, and T are joined with a line. Which statement best explains why Ben uses the same width to draw arcs from A and B which intersect at S? (5 points) Group of answer choices BQ = BS when ∠AQS ≅ BQS. AQ = AS when ∠AQS ≅ BQS. ∠AQS ≅ BQS when AS = BS and AQ = BQ. ∠AQS ≅ BQS when AS = BQ and BS = AQ.
Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

∠AQS ≅ ∠BQS when segments AQ and BQ are equal.

Step-by-step explanation:

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7 0
3 years ago
What did I do wrong?!
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(3n-2) x (4n+1) =0

All you need to do is to find what value of n makes each factor equal 0.

First Term:
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5 0
3 years ago
Please help &lt;3!!!!!!!!!
GREYUIT [131]

Answer:

D

Step-by-step explanation:

the picture is extremely diffuse and out of focus.

but I think I understood the content.

first the easiest part : the straight line on the right side of the graph.

we see the y increases exactly like the x. so, x increases by 2, then y increases by 2 too.

therefore the slope is 1 (y change / x change), and the function is simply y = x

and the line only starts with x=2 and goes on for all x greater than 2.

just for that alone it can be only D, because all the other answer options violate that behavior.

and the left part of the function must confirms this.

first of all, it has to be for x < 2 (again, only D).

and I found |-x²| really funny. this is the same as simply x², as a squared number can only be positive. so, making it negative and then taking the absolute value of that result creates the same original positive number again.

and x² can't be the function, because that would be a parabola that starts at the origin (0, 0), and then curves up left and right from there.

so, this can't be our function in the graph.

again, D is the the only fitting answer.

6 0
2 years ago
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