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<h3><u>The system of linear equations that represents the situation is:</u></h3>
a + b = 28
16a + 10b = 400
<h3><u>20 scented candles and 8 unscented candles were sold</u></h3><em><u>Solution:</u></em>
Let "a" be the number of scented candles sold
Let "b" be the number of unscented candles sold
From given,
Cost of 1 scented candles = $ 16
Cost of 1 unscented candles = $ 10
<em><u>The shop sells 28 candles today</u></em>
Therefore,
a + b = 28
b = 28 - a ------- eqn 1
<em><u>The shop sells 28 candles today and makes $400</u></em>
Therefore,
number of scented candles sold x Cost of 1 scented candle + number of unscented candles sold x Cost of 1 unscented candles = 400
16a + 10b = 400 ------ eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
16a + 10(28 - a) = 400
16a + 280 - 10a = 400
6a = 400 - 280
6a = 120
a = 20
<em><u>Substitute a = 20 in eqn 1</u></em>
b = 28 - 20
b = 8
Thus 20 scented candles and 8 unscented candles were sold