Help I just don’t know what I’m supposed to do?

Add. Write your answer as a fraction or as a whole or mixed number. 3 9 10 + 3 11 11

kherson [118]

we have

10 3/11 + 3 9/11=(10+3)+(3/11+9/11)=13+(12/11)=13=(13=(

3 0

1 year ago

Which expression is equivalent to ^4sqrt6/^3sqrt2?

BigorU [14]

$\dfrac{\sqrt[4]6}{\sqrt[3]2}=6^\frac{1}{4}:2^\frac{1}{3}=6^\frac{1\cdot3}{4\cdot3}:2^{\frac{1\cdot4}{3\cdot4}}=6^\frac{3}{12}:2^\frac{4}{12}=(6^3)^\frac{1}{12}:(2^4)^\frac{1}{12}\\\\=216^\frac{1}{12}:16^\frac{1}{12}=(216:16)^\frac{1}{12}=\sqrt[12]{\dfrac{216}{16}}=\sqrt[12]{\dfrac{27}{2}}\\\\\text{Answer:}\ 1)\ \sqrt[12]{\dfrac{27}{2}}$

4 0

3 years ago

Read 2 more answers

The manager of the commercial mortgage department of a large bank has collected data during the past two years concerning the nu

ZanzabumX [31]

The expected number of mortgages approved per week and the standard deviation of the distribution are 2.019 and 0.024 respectively.

The expected number of mortgages approved per week :

Mean = (Σfx ÷ Σf)

Expected Number approved = 210 ÷ 104 = 2.019

Hence, it is expected that 2.019 mortageahes would be approved per week.

The standard deviation :

Variance = [Σ(Xi - x)² ÷ Σf]

Standard deviation = √Variance

Variance = (59.5414 ÷ 104) = 0.0005698

Standard deviation = √0.0005698

Standard deviation = 0.024

Therefore, the expected value and standard deviation are 2.019 and 0.024 respectively.

Learn more :brainly.com/question/15528814

3 0

2 years ago

What is the area of the figure?

Orlov [11]

Answer:

90 in²

Step-by-step explanation:

The figure's area is that of four right triangles, each with legs of 6 in and 7.5 in. The area of each triangle is half the product of the leg lengths, so is ...

triangle area = (1/2)(6 in)(7.5 in)

Then the area of 4 of those triangles is ...

figure area = 4 · triangle area = 2(6 in)(7.5 in) = 90 in²

8 0

3 years ago

How do I solve question 6 through 8? Solve for me

rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

Question #6

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

Question #7

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

Question #8

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2