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saveliy_v [14]
2 years ago
5

What are the zero(s) of the function f(x) = 4x^2 - 36x/ x - 9

Mathematics
1 answer:
Anastaziya [24]2 years ago
3 0
To find -intercept/zero, substitute
So
0=4x^2-36x / 9-x
Now x should be #9 bcz 9-9=0
So
0=4x x(x-9)/x-9
0=4x
X=0
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