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3 years ago

Which of the following months would be the darkest at the South Pole?

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

5 0

Answer:

February

Step-by-step explanation:

February would be the darkest at the South Pole. In the month of February, the temperature raises to -38 to -51 degrees over south pole.

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Use trigonometric identities to solve each equation within the given domain.

Softa [21]

Answer:

A) X=pi/2 or X=-pi/2

B) X=pi/6 or X=-pi/6

C) X=pi/4 , 3pi/4, 5pi/4 and 7pi/4

D) X= 1-cos^2(x/2)

E) X= pi/3 +2pi N, 5pi/3+2pi N

Step-by-step explanation:

Don't even bother asking. :)

3 0

3 years ago

Rectangle ABCD has coordinates A(0,0), B(0,4), C(3, 0), and D(3, 4). If the

love history [14]

Hello~

The answer is C. (3,0)

Hope this helps!

Ary~

7 0

3 years ago

Question number 25, a.

ivann1987 [24]

23
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3 0

3 years ago

Show that 5x^2 + 2x - 3 < 0 can be written in the form | x + 1/5 | < 4/5

Sliva [168]

Step-by-step explanation:

First let solve the inequality

$5 {x}^{2} + 2x - 3 < 0$

Factor by grouping

$5 {x}^{2} + 5x - 3x - 3 < 0$

$5x(x + 1) - 3(x + 1)$

So the factor are

$(5x - 3)(x + 1)$

So the factor are

$x = \frac{3}{5}$

and

$x = - 1$

Solutions to a quadratic can be represented by a absolute value equation because remeber quadratics

creates 2 roots and/or double roots.

The inequality

$|x - b| < c$

works as

b is the midpoint between 2 roots. And c is the

$|x + b| = c$

We know that the midpoint between both roots is-1/5.

$|x - ( - \frac{1}{5} )| < c$

$|x + \frac{1}{5} | < c$

Let use roots 3/5

$| \frac{3}{5} + \frac{1}{5} | = \frac{4}{5}$

-1 works as well.

$| - 1 + \frac{1}{5} | = | - \frac{4}{5} | = \frac{4}{5}$

So the absolute value equation is

$|x + \frac{1}{5} | < \frac{4}{5}$

8 0

3 years ago

The product of 5 and x is at least 25

Lady bird [3.3K]

Answer: 5n≥25 and if you divide 5 on both sides, n≥5 (I don't know if you are supposed to solve or simply put it in the equation form).

Step-by-step explanation:

7 0

3 years ago