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Montano1993 [528]
3 years ago
12

Evaluate the inverse trigonometric function Sin^-1(-1). Give answers in both radians and degrees.

Mathematics
1 answer:
grin007 [14]3 years ago
4 0

Answer:

B) Sin^-1(-1) = 3pi/2 or 270°

D) Sin^-1(-1) = -pi/2 or -90°

Step-by-step explanation:

Sine function:

The sine function is -1 at 270º(-90º), which is 3pi/2 = -pi/2.

Inverse sine:

The input of the inverse sine function is a value, and the output are the angles which have the sine equal to the input.

Sin^-1(-1)

Angles for which the sine are -1, that is 3pi/2 or 270° and -pi/2 or -90°. Thus, options B and D are correct.

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Solve the following problems : Given: S, T, and U are the midpoints of RP , PQ , and QR respectively. Prove: △SPT≅△UTQ.
AleksandrR [38]

Answer:

Hence Proved △ SPT ≅ △ UTQ

Step-by-step explanation:

Given: S, T, and U are the midpoints of Segment RP , segment PQ , and segment QR respectively of Δ PQR.

To prove: △ SPT ≅ △ UTQ

Proof:

∵ T is is the midpoint of PQ.

Hence PT = PQ    ⇒equation 1

Now,Midpoint theorem is given below;

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

By, Midpoint theorem;

TS║QR

Also, TS = \frac{1}{2} QR

Hence, TS = QU (U is the midpoint QR) ⇒ equation 2

Also by Midpoint theorem;

TU║PR

Also, TU = \frac{1}{2} PR

Hence, TU = PS (S is the midpoint QR) ⇒ equation 3

Now in △SPT and △UTQ.

PT = PQ (from equation 1)

TS = QU (from equation 2)

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By S.S.S Congruence Property,

△ SPT ≅ △ UTQ ...... Hence Proved

6 0
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