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zepelin [54]
3 years ago
9

Find the 8th term of the sequence

Mathematics
2 answers:
Olegator [25]3 years ago
7 0

Answer:

d. \:  \frac{4}{3125}

Step-by-step explanation:

<h3>HOPE IT HELPS MUCH UNTO YOU</h3>
Paha777 [63]3 years ago
5 0

9514 1404 393

Answer:

  (d)  4/3125

Step-by-step explanation:

The first term is 100 and the common ratio is 20/100 = 1/5. The explicit formula for terms of a geometric sequence is ...

  an = a1·r^(n-1)

  an = 100·(1/5)^(n-1)

Then the 8th term is ...

  a8 = 100 ·(1/5)^(8-1) = 100·5^(-7) = 4/3125

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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

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DerKrebs [107]

Answer:

They are

Step-by-step explanation:

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AA is angle angle

The picture gives (( so that measns that (( and (( are congruent angles. The same with the (, it. is congruent to the other (.

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I thought of a number, added 26 to it, and then divided the result by 20.what is my number?
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Answer:

Step-by-step explanation:

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Solve 2(x + 1) = 2x + 2.<br> A All real numbers<br> B No solution<br> C 0<br> D 1
FrozenT [24]
2(x+1)=2x+2  if you factor the right side ..

2(x+1)=2(x+1)

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