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3 years ago

Which is the solution to the equation 3.5(2h+4.5)=57.75? Round to the nearest tenth if necessary

Mathematics

2 answers:

alexgriva [62]3 years ago

7 0

The answer is the option A, which is: A. $6$

The explanation for this problem is shown below:

1. You have the following equation:

$3.5(2h+4.5)=57.75$

2. Apply the distributive property and solve for $h$ , as following:

$7h+15.75=57.75\\ 7h=42\\ h=\frac{42}{7} \\ h=6$

As you can see, the correct answer is the option mentioned before.

BigorU [14]3 years ago

6 0

The equation given to us is: $3.5(2h+4.5)=57.75$

TO solve for $h$ , first divide both sides by 3.5

$2h+4.5=\frac{57.75}{3.5}=16.5$

Subtracting 4.5 from both sides we get:

$2h=16.5-4.5=12$

Finally, dividing both sides by 2, we will get the value of h as:

$h=\frac{12}{2}=6$

Therefore, Option A is the correct answer.

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Three boxes of supplies have an average (arithmetic mean) weight of 7 kilograms and a median weight of 9 kilograms. What is the

maria [59]

Answer:

Step-by-step explanation:

given data is:

mean = 7 kg
median = 9 kg
total number of boxes = 3

so since we know that the median is 9 and the total boxes are 3. We already know the weight of one of the three boxes.

so we can think of the sum of the three weights in ascending order as: A+9+B.

here A and B are the unknown weights of the remaining two boxes.

We can first use all of the given data in the mean formula

mean = (sum of all weights)/(number of boxes)

put all the known values in the formula

$7 = \frac{A+9+B}{3}$

and rearrange the formula so one of A and B as the subject.

$A = 21 - (9+B)$

now you can use the given values in the Multiple choices from the question and find the maximum value. try each value to be equal to B, so you can find A.

but you need to be smart about it, and keep in mind that the only one of the value of A and B should be greater than the median i.e. 9, or else that will rearrange the way we have set up our boxes:: A + 9 + B (ascending order).

start from (E), where B = 5

$A = 21 - (9+5)$

$A = 7$

here, no value is greater than the median: 3+9+7 (not ascending)

now check (D), where B = 4.

$A = 21 - (9+4)$

$A = 8$

here no value is greater than the median: 4+9+8 (not ascending)

now check (C), where B = 3

$A = 21 - (9+3)$

$A = 9$

here, one of the boxes is equal to the median: 3+9+9 (ascending)

you see a pattern here, the value of A is increasing, thus B is decreasing.

check (B), where B = 2

$A = 21 - (9+2)$

$A = 10$

here, you can realize that B = 2 is not correct since this is not maximum possible weight of the lightest box: 2+9+10 (ascending, but the weight of the lightest box is not maximum possible)

Since, we want maximum possible weight for the lightest box, that is only possible when B = 3 (maximum possible)

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3 years ago

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enot [183]

elimination means to get rid of one variable by altering the coefficients of variable (by multiplying and diving by some constant number)

in this case, if you just add the two equation, y gets cancelled you get 5x=20 or x=4

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What is the domain of the function?<br> x + 3<br> f(x) =<br> VX + 3

ahrayia [7]

Your question is a little ambiguous, but I am assuming that you meant to say the function $f(x) = x+3$

Thus, I am solving your question based on assuming the function such as

$f(x)=x+3$

But, it would still clear your concept, no matter what the function is.

Answer:

we conclude that

$\mathrm{Domain\:of\:}\:x+3\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

The graph is also attached.

Step-by-step explanation:

Given the function

$f(x)=x+3$

We know that the domain of a function is the set of input or argument values for which the function is real and defined.

As the function has no undefined points nor domain constraints.

Thus, the domain is

$-\infty \:$

Therefore, we conclude that

$\mathrm{Domain\:of\:}\:x+3\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

The graph is also attached.

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