The best option that gives a great conclusion about her acting career is Option C; Hedy Lamarr worked in America films with MGM Studios
<h3>What is the summary of his acting career?</h3>
Hedy Lamarr was a woman who had so many talents and was first known as a European film actress in the 1930s.
Hedy Lamarr began acting in American films with MGM Studios in the late 1930s and early 1940s. She did not have any formal training, but she did not allow that to stop her from teaching herself in her spare time which really helped her advance forward in the acting industry.
We can conclude that the best option that gives a great conclusion about her acting career is Option C.
The missing options are;
a. Hedy Lamarr wanted more opportunities to speak while acting
b. Hedy Lamarr was the first European actress of the 1930s
c. Hedy Lamarr worked in America films with MGM Studios
d. Hedy Lamarr was content with her contribution to film.
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The labels are not found here but allele frequencies depend on the number of different gene variants in a given population.
<h3>What is an allele?</h3>
An allele is a given gene variant received from parents, which is found in a specific gene locus in a chromosome.
Allele frequency makes reference to the number of that a given gene variant or allele exhibits in a population or sample.
In conclusion, the labels are not found here but allele frequencies depend on the number of different gene variants in a given population.
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Uhmmm ma’am/sir i am not sure what’s going on exactly
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
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An activity made by the school with the school in the school, but is not graded and doesn’t take any part during the grading process
