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3 years ago

2

Mathematics

1 answer:

drek231 [11]3 years ago

4 0

Answer:

Step-by-step explanation:

4 and 1 should be tirlls

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Okie help help math math math

liraira [26]

Answer:

$\displaystyle y = -3x + 9$

Step-by-step explanation:

First, find the rate of change of the line:

$\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{-6 + 3}{-1 + 2} = m \hookrightarrow \frac{-3}{1} = m \\ \\ \boxed{-3 = m}$

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Now plug all the information into the Slope-Intercept Formula. It does not matter which ordered pair is chosen:

$\displaystyle 3 = -3[2] + b \hookrightarrow 3 = -6 + b; 9 = b \\ \\ \boxed{\boxed{y = -3x + 9}} \\ \\ OR \\ \\ 6 = -3[1] + b \hookrightarrow 6 = -3 + b; 9 = b \\ \\ \boxed{\boxed{y = -3x + 9}}$

I am joyous to assist you at any time.

3 0

2 years ago

Eleven more than four times a number is 23

goblinko [34]

3 is the original number
You have to do reverse operations
23-11=12
12/4=3

7 0

3 years ago

If 4x - 8 = 4 , find the value of x

Wittaler [7]

Answer:

x=3

Step-by-step explanation:

4x-8=4

4x=12

4x/4=12/4

x=3

3 0

3 years ago

Read 2 more answers

Z 3 +4 z 2 + z 3 +4 4z 2 −6z

sergeinik [125]

Answer:

Step-by-step explanation:

7 0

3 years ago

The estimated probability of a football player scoring a touchdown during a particular game is 39%. Of several simulations of th

VLD [36.1K]

Answer:

The percentage of the simulations of two games that the football player would most likely get a touchdown in each of the two games = 15.21%

Step-by-step explanation:

The probability of scoring a touchdown in one game for the football player = 39% = 0.39

Probability of scoring a touchdown in each of the two consecutive games = (Probability of scoring a touchdown in the first game) × (Probability of scoring a touchdown in the second game)

Since the probability of scoring a touchdown in each game the football player plays in is independent of one another.

Probability of scoring a touchdown in the first game = Probability of scoring a touchdown in the second game = 0.39

Probability of scoring a touchdown in each of the two consecutive games = 0.39 × 0.39 = 0.1521

If 100 simulations of the two games are made, the player scores in each of the two games in 15.21 of them, hence, the percentage of the simulations that the football player would most likely get a touchdown in each of the two games = 15.21%

Hope this Helps!!

4 0

4 years ago