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Lyrx [107]
3 years ago
7

Round the number 18.374 to the nearest hundredth

Mathematics
2 answers:
Lelu [443]3 years ago
6 0
It would be 18.37 because 4 is smaller then 5, so you round down.
daser333 [38]3 years ago
6 0
18.37 Is Your Answer. Hope This Helps You
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30 points and Brainliest!!
diamong [38]
Thats easy .


the 2 figures aren't the same because they're both not the same size and one 
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3 0
3 years ago
Simplify: -7 • 12<br><br>Giving brainliest^^<br><br>A) -84<br><br>B) -74<br><br>C) 74<br><br>D) 84
riadik2000 [5.3K]
The answer should be A) -84
7 0
3 years ago
Read 2 more answers
Sam and Jeremy have ages that are consecutive odd integers. The product of their ages is 783, which equation could be used to fi
stepladder [879]
(2x+1)=Jeremy´s age
(2x+3)=Sam´s age.
we suggest this equation:
(2x+1)(2x+3)=783
4x²+6x+2x+3=783
4x²+8x-780=0
x²+2x-195=0

We solve this quadratic equation:
x=[-2⁺₋√(4-4*1*(-195))]/2=(-2⁺₋28)/2

x₁=(-2-28)/2=-15 this solution is not valid.
x₂=(-2+28)/2=13

Jeremy´s age=2x+1=2*13+1=27
Sam´s age=2x+3=2*13+3=29



7 0
3 years ago
Which statement is correct?
Anika [276]

3\frac{5}{8} =3.625&#10;\\ \\3.6

8 0
3 years ago
Consider the following planes. x + y + z = 6, x + 7y + 7z = 6 (a) Find parametric equations for the line of intersection of the
Lelechka [254]

Answer:

a.x=6,y=-6t,z=6t

b.\theta=29.5^{\circ}

Step-by-step explanation:

We are given that

x+y+z=6

x+7y+7z=6

a.Substitute z=0

x+y=6...(1)

x+7y=6..(2)

Subtract equation (1) from equation (2)

6y=0

y=0

Substitute y=0 in equation(1)

x=6

The point (6,0,0) lie on a line.

r_0=(x_0,y_0,z_0)=(6,0,0)

Let A=

B=

A\times B=\begin{vmatrix}i&j&k\\1&1&1\\1&7&7\end{vmatrix}

A\times B=i(7-7)-j(7-1)+k(7-1)=-6j+6k

Therefore, the vector a'=(a,b,c)=

Line is parallel to vector a' and passing through the point (6,0,0).

The parametric equation is given by

x=x_0+at,y=y_0+bt,z=z_0+ct

Using the formula

The parametric equation is given by

x=6,y=-6t,z=6t

Angle between two plane

a_1x+b_1y+c_1z=d_1

and a_2x+b_2y+c_2z=d_2

cos\theta=\frac{(a_1,b_1,c_1)\cdot (a_2,b_2,c_2)}{\sqrt{a^2_1+b^2_1+c^2_1}\cdot \sqrt{a^2_2+b^2_2+c^2_2}}

Using the formula

cos\theta=\frac{(1,1,1)\cdot(1,7,7)}{\sqrt{1+1+1}\times \sqrt{1+7^2+7^2}}

cos\theta=\frac{1+7+7}{\sqrt 3\times 3\sqrt{11}}

cos\theta=\frac{15}{3\sqrt{33}}}=\frac{5}{\sqrt{33}}

\theta=cos^{-1}(0.87)=29.5^{\circ}

Where \theta in degree.

3 0
2 years ago
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