Answer:

Step-by-step explanation:
Given
The attached functions
Required
Find f(9)
We have:

So:



1 2/5 BOOM mathed 4 dayz ~ vinny
Given:
Northern Florida: 2,000 patients ; 64% experienced flulike symptoms during December
Southern Florida: 3,000 patients ; 54% experienced flulike symptoms during December
Standard error = √[p(1-p)/n]
NF = √[0.64(1-0.64)/2000] = √[(0.64*0.36)/2000] = 0.0107 or 1.07%
SF = <span>√[0.54(1-0.54)/3000] = √[(0.54*0.46)/3000] = 0.0091 or 0.91%
smallest margin of error for a 95% confidence interval
NF: Em </span>≈ 0.98/√2,000 = 0.98/44.72 = 0.0219 or 2.19%
<span>SF: Em </span>≈ 0.98/√3,000 = 0.98/54.77 = 0.0178 or 1.78%
<span>
MY ANSWER:
</span><span>B.The southern Florida study with a margin of error of 1.8%.</span>
These are the events in the question above:
<span>D - has disease
</span>
<span>H - healthy (does not have disease)
</span>
<span>P - tests positive </span>
<span>It is the probability that a person has the disease AND tests positive divided by the probability that the person tests positive.
</span>
Sick, + [.04*.91] = .0364
<span>Sick, - [.04*.09] = .0036 </span>
Healthy, + [.96*.04] = 0.0384
<span>Healthy, - [.96*.96] = .9216
</span>
.0364 / (.0364 + .0.0384) = 0.487
When rounding, only look at the number to the immediate right of the place you are rounding to. In this example that would be the 4. If the number is 5 or more, round up, if it is 4 or less, round down.
Therefore 234.6 rounds to 230
Final answer:
230