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Nataly [62]
3 years ago
8

If a spacecraft was parked on Venus and needed to make a flight to Jupiter, how far would it need to travel?

Mathematics
2 answers:
babymother [125]3 years ago
5 0

Answer:

Venus is slightly nearer Earth than the sun, 0.512 astronomical units (AU) distant (47.6 million miles, or 76.5 million kilometers), while Jupiter is 6.083 AU away (565 million miles, or 910 million km) on the far side of the sun

Step-by-step explanation:

saul85 [17]3 years ago
3 0
<span>It will be exactly 416,399,477 miles. 
</span><span>
</span>
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F(x)=x^2 What is g(x)?
Vikki [24]

Answer:

answer is D

Step-by-step explanation:

4 0
3 years ago
Translate the following verbal statement into an algebraic expression. Use x for your variable.
mafiozo [28]

Answer:

<u>x²/11 + 8</u>

Step-by-step explanation:

We can decipher this algebraic expression going step by step.

1) "Eight more", meaning +8 (we can add this on later).

2) The "quotient of a number (x) squared and eleven", a quotient by definition means the answer to a quantity divided by another. The quantity in this case being x² divided by 11 (so, x²/11).

3) We can combine both of these, getting x²/11 + 8.

Your expression is x²/11 + 8.

- Similarly, you could reposition this equation like 8 + x²/11 (due to the communicative property of addition). Both answers would be acceptable.

5 0
3 years ago
In a recent survey of college professors, it was found that the average amount of money spent on entertainment each week was nor
Alenkinab [10]

Answer:

0.0918

Step-by-step explanation:

We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.

The mean and standard deviation of average spending of sample size 25 are

μxbar=μ=95.25

σxbar=σ/√n=27.32/√25=27.32/5=5.464.

So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.

The z-score associated with average spending $102.5

Z=[Xbar-μxbar]/σxbar

Z=[102.5-95.25]/5.464

Z=7.25/5.464

Z=1.3269=1.33

We have to find P(Xbar>102.5).

P(Xbar>102.5)=P(Z>1.33)

P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)

P(Xbar>102.5)=0.5-0.4082

P(Xbar>102.5)=0.0918.

Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.

5 0
3 years ago
Find the complement of the angle shown
Archy [21]
Supplementary = 180°
Complementary = 90°

180° - 52° = 128°
90° - 52° = 38°

Hope this Helps!!
6 0
3 years ago
68.64 is 78% of what
icang [17]
53.5392 is the answer
6 0
3 years ago
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