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Leona [35]
2 years ago
15

Subtract from (4x- 5y+3z) from the sum of (9x+2y-3z), (-10x+ y- z) and (2x+ 3y+ 7z).Explain​

Mathematics
2 answers:
nikklg [1K]2 years ago
7 0

Step-by-step explanation:

★First let's find out the <u>sum.</u>

(9x + 2y - 3z) + (-10x + y - z) + (2x + 3y + 7z)

= (9x - 10x + 2x) + (2y + y + 3y) + (-3z - z + 7z)

= (x) + (6y) + (3z)

= x + 6y + 3z

<u>★</u><u>Now subtraction:</u>

(x + 6y + 3z) - (4x - 5y + 3z)

= (x + 6y + 3z - 4x + 5y - 3z)

= (x - 4x + 6y + 5y + 3z - 3z)

<h3>= -3x + 11y</h3>

★∴Answer is <u> -3x + 11y</u>

<h2><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h2>
Allushta [10]2 years ago
5 0

Answer: -13x -3y + 12z

Step-by-step explanation:

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2/3 * 1/2+ 3/4 /1+ 1/6
In-s [12.5K]

Answer:

2/3 * 1/2+ 3/4 /1+ 1/6 =1.25

1.25

Step-by-step explanation:

3 0
2 years ago
Order each set of numbers from least to greatest.<br><br><br> PLZ HELP ASAP
Wittaler [7]

Answer:

<h3><u>7. Ans ;</u></h3>

\frac{41}{3}  < 14 <  \sqrt{200}

<h3><u>8</u><u>.</u><u> </u><u>Ans</u><u> </u><u>;</u></h3>

<u>0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }</u>

Step-by-step explanation:

<h3><u>7. Ans ;</u></h3>

\sqrt{200}  = 10 \sqrt{2}  = 14.1 \\ 14 = 14 \\  \frac{41}{3}  = 13.6

So ;

\frac{41}{3}  < 14 <  \sqrt{200}  \\ 13.6 < 14 < 14.1

<h3><u>8. Ans ;</u></h3>

\frac{2}{3}  = 0.66 \\  \sqrt{ \frac{9}{16} }   =   \frac{3}{4}  = 0.75 \\ 0.6 = 0.6

So ;

0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }  \\ 0.6 < 0.66 < 0.75

I hope I helped you^_^

6 0
2 years ago
A rope is 225 centimeters long.
n200080 [17]

Answer:

This is impossible, unless you meant centimeters. If you did, then the answer would be 113.

Step-by-step explanation:

225 - 112 = 113.

8 0
3 years ago
How to do complete the number line using the following fractions
Sloan [31]
You line them up from smallest to greatest
5 0
3 years ago
Answer 1-6 (about square root)
Taya2010 [7]

Answer:

1. For a cube, volume = edge^{3}

2. \sqrt[3]{volume} = edge

3. Volume of the cube = 216 so, the edge = \sqrt[3]{216} = 6

4. 1st blank = 6

   2nd blank = 6

   3rd blank = 216

   4th blank = 216

5. 6 is the edge

6. As the room is a square and we have to find the side

Area = 121

Edge = \sqrt[2]{121} = 11

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

4 0
3 years ago
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