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3 years ago

Solve by factoring Y^2+5y+6=0 •-3 •4,8 •2,3 •-4,3

Mathematics

2 answers:

rjkz [21]3 years ago

7 0

Step-by-step explanation:

y²+5y+6=0

y²+2y+3y+6=0

y(y+2)+3(y+2)=0

(y+2)(y+3)=0

:. y=2,3

option C.

hope this helps you.

Anon25 [30]3 years ago

3 0

Answer:

Step-by-step explanation:

Y^2+5y+6=0

5^2 - 4*2*6

25-48

23 i

-5 +4.79i => -0.21 => 0.5i

2*2 4

-5 +4.79i => -9.79 => 2.44i

2*2 4

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4 years ago

What is the value of 7 ^−3 ^ −1 for = −2 and = 4?

andrey2020 [161]

Answer:

d. −7/32

Step-by-step explanation:

The expression that we have to evaluate in this problem is:

$7x^{-3}y^{-1}$

We have to evaluate this expression for:

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We start by rewriting the expression by rewriting it using the following:

$a^{-n}=\frac{1}{a^n}$

So the expression can be rewritten as

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3 years ago

Question one: what is the solution to the system shown ?

Ann [662]

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Step-by-step explanation:

Cuz 2(-1)+3(4)=14

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3 years ago

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7nadin3 [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Veronika [31]

Answer:

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3 years ago

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