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natulia [17]
3 years ago
9

Help or the gremlins under your bed will eat all your cookies

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Answer:

what do you need help with exactly

Step-by-step explanation:

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The sum of 3 consecutive integers is 294. Find the 3 integers.
TiliK225 [7]

Divide the total by 3 to get the middle value:

294 /3 = 98

Now the 3 numbers are consecutive, so use the numbers on each side of 98:

Smallest = 97

middle = 98

Largest = 99

7 0
3 years ago
How do you find the complex and real roots for x^4-3x^2+2=0
pogonyaev
X^4 - 3x^2 + 2 = 0
(x^2 - 2)(x^2 - 1) = 0

so either x^2 - 2 = 0  or x^2 - 1 = 0

so x^2 = 2 or x^2 = 1

so x = sqrt 2 , - sqrt2, 1 , -1   Answer

all the roots are real
6 0
4 years ago
Given g(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Bx%5E2%2B2x%7D" id="TexFormula1" title="\frac{3}{x^2+2x}" alt="\f
sweet [91]

We know that g(x) = \frac{3}{x^2+2x}

We have to find g^-1(x)  or inverse of g(x)

Inverse of g(x) can be determined by equating g(x) to y, and determining the value of x in terms of y

g(x) = y = \frac{3}{x^2+2x}

⇒ y × (x² + 2x) = 3

⇒ yx² + 2xy = 3

⇒ yx² + 2yx - 3 = 0

Determining the roots of x using:

x = \frac{-b + \sqrt{b^{2} - 4ac}}{2a} OR x = \frac{-b - \sqrt{b^{2} - 4ac}}{2a} , where a is coefficient of x², b is coefficient of x, and c is the constant

⇒ x = \frac{-2y + \sqrt{4y^2 - 4(2y)(-3)}}{2y} OR x = \frac{-2y - \sqrt{4y^2 - 4(2y)(-3)}}{2y}

⇒ x = \frac{-2y + \sqrt{4y^2 + 24y}}{2y} OR x = \frac{-2y - \sqrt{4y^2 + 24y}}{2y}

Hence, g^-1(x) = \frac{-2y + \sqrt{4y^2 + 24y}}{2y} OR x = \frac{-2y - \sqrt{4y^2 + 24y}}{2y}

7 0
4 years ago
Read 2 more answers
Help please can someone show me how to solve this
Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

so first make an equation...

10x=2x-32

then do distributive property

10x-2x=2x-32-2x

8x=-32

then divide negative 32 by 8

x= negative 4

7 0
4 years ago
2: CA &gt; Chapter 7 &gt; Section Exercises 7.5 &gt; Exercise 6
Pani-rosa [81]
Yes....................
7 0
3 years ago
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