<h3>
Answer: 20 lawns</h3>
Work Shown:
8 lawns = 2 hours
4 lawns = 1 hour (divide both sides by 2)
20 lawns = 5 hours (multiply both sides by 5)
I don’t see any graph attached to the question
4sin²(x) = 5 - 4cos(x)
4{¹/₂[1 - cos(2x)]} = 5 - 4cos(x)
4{¹/₂[1] - ¹/₂[cos(2x)]} = 5 - 4cos(x)
4[¹/₂ - ¹/₂cos(2x)] = 5 - 4cos(x)
4[¹/₂] - 4[¹/₂cos(2x)] = 5 - 4cos(x)
2 - 2cos(2x) = 5 - 4cos(x)
- 2 - 2
-2cos(2x) = 3 - 4cos(x)
-2[2cos²(x) - 1] = 3 - 4cos(x)
-4cos²(x) + 2 = 3 - 4cos(x)
- 2 - 2
-4cos²(x) = 1 - 4cos(x)
-4cos²(x) + 4cos(x) - 1 = 0
4cos²(x) - 4cos(x) + 1 = 0
[2cos(x) - 1]² = 0
2cos(x) - 1 = 0
+ 1 + 1
2cos(x) = 1
2 2
cos(x) = ¹/₂
cos⁻¹[cos(x)] = cos⁻¹(¹/₂)
x = 60, 300
x = π/3, 5π/3
[0, 2π) = 0 ≤ x < 2π
[0, 2π) = 0 ≤ π/3 ≤ 2π or 0 ≤ 5pi/3 < 2π
Answer:3(x-9) is expressed as 3x-27
Step-by-step explanation: 3(Xminus9)
3(X-9)
Use 3 to open the bracket by using 3 to multiply everything in the bracket.
Then you will get
3x-27
Answer:
the force that must be applied by the driver to release the clutch is 21 lb
Step-by-step explanation:
Data provided:
clutch linkage on a vehicle has an overall advantage = 24:1
Applied force by the pressure plate = 504 lb
Now,
the advantage ratio is given as:
advantage ratio = 
on substituting the respective values, we get
= 
or
Force applied by the driver to release the clutch = 
or
Force applied by the driver to release the clutch = 21 lb
Hence,
the force that must be applied by the driver to release the clutch is 21 lb
