a. The reason why this question is a binomial experiment is based on the fact that it is made up of an independent sample, it has a number that is fixed and a probability.
Each event is made up of two outcomes and they are random with the same success rate.
<h3>b. How to solve probability that exactly 5 had a bachelor</h3>
we have the following data n = 12, p = 0.27 and k = 5
We have to use the function to solve electronically
binompdf(n,p,k)
input the values
= binompdf(12,0.27,5)
This gives us
= 0.1255
<h3>(C) Probability that fewer than 5 have bachelor</h3>
We use the formula below
= binompdf(12,0.27,5-1)
This is = 0.7984
D. Probability of at least 5
1 - probability of fewer than 5
= 1 - 0.7984
= 0.2016
How to solve for the Mean = n*p
n = 12 , p = 0.27
Mean = 12*0.27 = 3.24
and
standard deviation = √npq
n = 12, p = 0.27 , q = 1- 0.27
= 0.73
sd = √12*.27*.73
= 1.54
Read more on binomial experiment here:
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34.95 x 18%= 6.29
34.95-6.29= 28.66
$28.66 is the sale price
Answer:
X = 18
Y = 18
Step-by-step explanation:
first make two equation like
x + y = 36
1180x + 125y = 23490
from equation one we have
y = 36- x
put in second equation
1180x + 125 (36-x) = 23490
1180x + 4500-125x = 23490
1055x = 23490-4500
x = 18990/1055
x = 18
put this x value in equation 1 to find y value
18+ y = 36
y = 36-18
y = 18
we know that
If the point belongs to the graph, then the point must satisfy the equation
we will proceed to verify each case
<u>case A.)</u> 
The point is 
Verify if the point satisfy the equation
For
find the value of y in the equation and compare with the y-coordinate of the point



therefore
the equation
not passes through the point 
<u>case B.)</u> 
The point is 
Verify if the point satisfy the equation
For
find the value of y in the equation and compare with the y-coordinate of the point



therefore
the equation
passes through the point 
<u>case C.)</u> 
The point is 
Verify if the point satisfy the equation
For
find the value of y in the equation and compare with the y-coordinate of the point



therefore
the equation
not passes through the point 
<u>case D.)</u> 
The point is 
Verify if the point satisfy the equation
For
find the value of y in the equation and compare with the y-coordinate of the point



therefore
the equation
passes through the point 
therefore
<u>the answer is</u>

