Answer:
06959399449444rifotvovty5
Distribute the 3a^n to all the other values then solve...
(3a^n*a^n)+(3a^n*a^n)+(3a^n*-1)
4a^2n+4a^2n-3a^n=
8a^2n-3a^n
The standard form of the equation of a circle is:
Where the point (a,b) represents the centre and r is the radius. So, given your information, the equation will be:
Answer
Step-by-step explanation:
The area would be length times width. x(4x+8) =96
4x^2+8x = 96
4x^2+8x-96=0. We need to factor.
It would be factored to (4x-16)(x+6) = 0
x would be -6 (x+6=0)
or x would be 4 (4x-16=0)
Why would the width be negative?!? So the answer is 4
<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
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