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OLEGan [10]
3 years ago
15

Order these from least to greatest: |–15|, |4|, –|15|, |–5|

Mathematics
2 answers:
Alenkinab [10]3 years ago
6 0

-/15/, /4/, /-5/,/ -15/

Tasya [4]3 years ago
4 0
/-15 /-15/ -5/ -4 / is from least to greatest
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Use the distributive property to simplify each expression<br> (2b - 10) 3.2
Darya [45]

Answer: 6.4b - 32

Step-by-step explanation:

4 0
3 years ago
I GIVE BRAINLIEST PLS HELP
ioda
The answer is 8
Here's why:
{ ( \frac{( {6}^{7}) \times ( {3}^{3})  }{(  {6}^{6}) \times ( {3}^{4}  ) } )}^{3}  =   \\ ( \frac{6}{3} ) ^{3}  =  \\ \frac{216}{27}  = 8
The exponents are subtracted one from another when divided.
\frac{ a ^{b} }{ {a}^{c} } =  {a}^{b - c}
We can look at the problem this way:
( \frac{6^{7} }{6 ^{6} }  \times  \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6}  \times  {3}^{3 - 4} ) =  \\ ({6}^{1}  \times  {3}^{ - 1} )
Since we have the power of -1 on the 3, we apply this rule:
{a}^{ - b}  =  \frac{1}{ {a}^{b} }
Also this rule because we have the power of 1 on the 6:
{a}^{1}  = a
Then we get this:
(6 \times  \frac{1}{3} )^{3}  = ( \frac{6}{3} )^{3}
We apply the rule:
( \frac{a}{b}) ^{c}   =  \frac{ {a}^{c} }{ {b}^{c} }
We get this:
\frac{{6}^{3} }{ {3}^{3} } =  \frac{216}{27}  = 8
4 0
3 years ago
Find the nth term of 67,56,45,34
kvv77 [185]

Answer:

  an = 67 -11(n -1)

Step-by-step explanation:

The terms of your arithmetic sequence have a common difference of -11. The first term is 67.

These values can be used in the generic formula for the n-th term:

  an = a1 +d(n -1) . . . . . . first term a1, common difference d

  an = 67 -11(n -1) . . . . . formula for the n-th term

7 0
3 years ago
What does 13m2n3p + 21mp2 equal when completely factored?
nekit [7.7K]
 Your question factored out would be 13mn^3 + 21p 

4 0
3 years ago
Consider the function f(x) = x(x – 4). If the point (2 + cy) is on the graph of f(x), the following point will also be on the gr
kakasveta [241]

Answer:

(2-cy) is the correct answer for the problem

3 0
3 years ago
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