Answer:
m∠K = 37° and n = 31
Step-by-step explanation:
A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:
- a² = b² +c² -2bc·cos(A)
- k² = 31² +53² -2·31·53·cos(37°)
<h3>Comparison</h3>
Comparing the two equations, we note these correspondences:
Comparing these values to the given information, we see that ...
- KN = c = 53 . . . . . . . . . . matching values 53
- NM = a = k . . . . . . . . . . . matching values k
- KM = b = n = 31 . . . . . . . matching values 31
- ∠K = ∠A = 37° . . . . . . . matching side/angle names
Abby apparently knew that ∠K = 37° and n = 31.
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<em>Additional comment</em>
Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.
Vertex and angle K are opposite side k, also called side NM in this triangle.
Answer:
(f/g)(8)= f(8)/g(8)= = 65/41
Step-by-step explanation:
f(x)=3 - 2x
g(x)=1/x +5
The easiest approach is to eval first the point in every function before performing the division, thus we have that:
f(8)= 3-2*8=-13
g(8)=1/8 +5= 41/5
Now, (f/g)(8)= f(8)/g(8)= 13 / (41/5) = 65/41
The answer is -8/15 because you need to cancel out the variables first
Answer:
D
Step-by-step explanation:
4x + 3 < 3x + 6 ( subtract 3x from both sides )
x + 3 < 6 ( subtract 3 from both sides )
x < 3 → D
