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2 years ago

Hi I need help and saw that this app could help me

Mathematics

1 answer:

r-ruslan [8.4K]2 years ago

3 0

Answer:

A would be your awnswer

Step-by-step explanation:

You might be interested in

Andres tiene una colección de sellos que puede agrupar de 12 en 12, de 16 en 16 y de 18 en 18 sin que sobre ninguno.¿Cuál es el

Murljashka [212]

Answer:

La respuesta a tu pregunta es: 135 sellos

Step-by-step explanation:

Datos

Agrupar de 12 en 12

Agrupar de 16 en 16

Agrupar de 18 en 18

Obtener el mcm

12 16 18 2

6 8 9 2

3 4 9 2

3 2 9 2

3 1 9 3

1 3 3

mcm = 2⁴ 3² = 135

5 0

2 years ago

A physics class is building a bottle rocket. Last week, it flew for 26.189 seconds. This week, it flew for 34.9 seconds. How muc

fredd [130]

Answer:

26.189 - 34.9

Step-by-step explanation:

26.189 - 34.9 = 8.711

8 0

2 years ago

An animal rescue group tracks how their marketing impacts the pet adoptions that occur each year. A record of adoptions for a 12

jenyasd209 [6]

Answer:

Step-by-step explanation:

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8 0

1 year ago

4x+7y=2 help . Pls.

solong [7]

Answer:

x = 2-7y over 4

Step-by-step explanation:

4x+7y=2

-7y -7y

4x = 2 - 7y

/4 /4

x=2 - 7y/4

6 0

3 years ago

Mark A machine has two parts labeled A and B. The probability that part A works for one year is 0.8 and the probability that par

Mrrafil [7]

Answer:

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.

This means that $P(A) = 0.8, P(B) = 0.6$

The probability that at least one part works for one year is 0.9.

This means that: $P(A \cup B) = 0.9$

We also have that:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$0.9 = 0.8+0.6 - P(A \cap B)$

$P(A \cap B) = 0.5$

Calculate the probability that part B works for one year, given that part A works for one year.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.5}{0.8} = 0.625$

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

3 0

2 years ago