You can think of x && y || z as equivalent to: int func (int x, int y, int z) { if (x) { if (y) { return true; } } if (z) { return true; } return false; } Since both x and y are fixed to be non-zero values the first return statement is always hit. thats what i think
The answer would be 20 because you have 5 blocks that are cut into 1/4. It doesn't say anything about any of the pieces disappearing or being used yet so you multiply 4*5 and then you get the answer.
The answer should be E. 223- 6s = 0
The probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.
Given mean of 30 minutes and standard deviation of 7.5 minutes.
In a set with mean d and standard deviation d. , the z score is given as:
Z=(X-d)/s.
where d is sample mean and s is standard deviation.
We have to calculate z score and then p value from normal distribution table.
We have been given d=30, s=7.5
p value of Z when X=44 subtracted by the p value of Z when X=16.
When X=44,
Z=(44-30)/7.5
=14/7.5
=1.87
P value=0.9686
When X=16
Z=(16-30)/7.5
=-1.87
P Value=0.0314.
Required probability is =0.9686-0.0314
=0.9372
=93.72%
Hence the probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.
Learn more about z test at brainly.com/question/14453510
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Answer:
7
Step-by-step explanation:
You would need 7 weeks because there is still 1 assessment after 6 weeks.
