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IRISSAK [1]
3 years ago
7

7. What is the surface area of the sphere?

Mathematics
1 answer:
atroni [7]3 years ago
6 0

Answer:

C

Step-by-step explanation:

The surface area (A) of a sphere is calculated as

A = 4πr² ← r is the radius

The diameter is given as 10, hence r = 5

A = 4π × 5² = 4π × 25 = 100π ≈ 314.16 mi² ( to 2 dec. places )

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A postcard in the shape of a parallelogram has an area of 12in^2. What are two possible lengths of bases and heights for the pos
Tpy6a [65]

A postcard is in the shape of a parallelogram. A parallelogram  is a quadrilateral with two pair of parallel sides, opposite sides and opposite angles are equal.

Since, the postcard has an area of 12 square inches.

Since, area of parallelogram = base \times height

As area of parallelogram is 12, it means that the product of base and height is 12 square inches.

So, the possible dimensions of postcard are 3 inches and 4 inches and 2 inches and 6 inches.

So, base = 3 inches , height = 4 inches or base = 4 inches , height = 3 inches.

So, base = 2 inches, height = 6 inches or base = 6 inches , height = 2 inches.

8 0
3 years ago
A manager of a grocery store wants to determine if consumers are spending
ololo11 [35]

Answer:

1. The error in the assumption is taking the sample mean, \bar x, as being equal to the population mean, μ

2. To correct the error, the manager will need to generate the confidence interval based on the population standard deviation on the acceptable values of the mean using the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

We note that from the central limit theorem as the size of the sample, n, becomes more and more larger, the mean of the sample, \bar x, approaches that of the population mean, μ, therefore as the grocery store manager uses the sample mean as the population mean's point estimate an error will be observed based on the size of the sample compared to the population, where the difference between the two means (the population mean and the sample mean) is \left | \bar{x} - \mu \right |

1. The error in the assumption is taking the sample mean, \bar x, as being equal to the population mean, μ

2. To correct the error, the manager will need to generate the confidence interval based on the population standard deviation on the acceptable values of the mean using the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where:

σ = Population standard deviation = $30

z = z value at 95% confidence level = 1.96

\bar x = Sample mean $160

n = Sample size = 10

Plugging in the values, we have;

$141.4 < \bar x < $178.6

Hence the expected value of the mean should be between $141.4 and $178.6.

7 0
3 years ago
Help me please
kari74 [83]

Answer:

\frac{ \cos(80) }{ \sin(10) }  +  \frac{ \sin(20) }{ \cos(70) }  = 2 \\  \frac{ \cos(90 - 10) }{ \sin(10) }  +  \frac{ \sin(20) }{ \cos(9 0 - 20) }  = 2 \\  \frac{ \sin(10) }{ \sin(10) }  +  \frac{ \sin(20) }{ \sin(20) }  = 2 \\ 1 + 1 = 2 \\ 2 = 2 \\  \\  \frac{ \cot(40) }{ \tan(50) }  +  \frac{ \cos(65) }{ \sin(115) }  = 2 \\  \frac{ \cot(90 - 50) }{ \tan(50) }  +  \frac{ \cos(65) }{ \sin(90 + 65) }  = 2 \\  \frac{ \tan(50) }{ \tan(50) }  +  \frac{ \cos(65) }{ \cos(65) }  = 2 \\ 1 + 1 \\  = 2

6 0
3 years ago
Please may someone help with c
german

Step-by-step explanation:

Distance between two villages = d

(a) \:  \frac{4}{5}  \: of \: d =  \frac{4}{5} d \\  \\ (b) \:  \frac{3}{4}  \: of \: d =  \frac{3}{4} d  \\  \\ (c) \: \frac{4}{5} d -   \frac{3}{4} d = 1.5 \\  \\  \therefore \:   \bigg(\frac{4}{5} -   \frac{3}{4} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{4 \times 4 - 3 \times 5}{5 \times 4} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{16- 15}{20} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{1}{20} \bigg) d = 1.5 \\  \\ \therefore \: d = 1.5 \times 20 \\  \\ \:  \:  \:  \:  \:  \huge \orange{ \boxed{{ \therefore \: d = 30}}}

4 0
3 years ago
31.75 as a improper and mixed fraction
Aleksandr [31]
31.75 as an improper fraction is 127/4. The mixed number fraction is 31 3/4.
3 0
3 years ago
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