1. First transformation is rotation rotation of 180 about the origin. This transformation has a rule:
(x,y)→(-x,-y).
If points E(-2,-4), F(-1,-1), D(-2,-1) are vertices of triangle EFD, then
- E(-2,-4)→E''(2,4),
- F(-1,-1)→F''(1,1),
- D(-2,-1)→D''(2,1).
2. Second transformation is translation 1 unit left with a rule
(x,y)→(x-1,y).
Then
- E''(2,4)→E'(1,4),
- F''(1,1)→F'(0,1),
- D''(2,1)→D'(1,1).
Answer: 1st: rotation of 180 about the origin; 2nd: translation 1 unit left.
Answer:
1) By SAS theorem, ΔADE≅ΔCDF
2) By SSS theorem, ΔBDE≅ΔBDF
Step-by-step explanation:
Consider isosceles triangle ABC (see diagram).
1. In triangles ADE and CDF:
- AD≅DC (since BD is median, then it divides side AC in two congruent parts);
- AE≅CF (given);
- ∠A≅∠C (triangle ABC is isosceles, then angles adjacent to the base are congruent).
By SAS theorem, ΔADE≅ΔCDF.
2. In triangles BDE and BDF:
- side BD is common;
- DE≅DF (ΔADE≅ΔCDF, then congruent triangles have congruent corresponding sides);
- BE≅FB (triangle ABC is isosceles, AB≅BC, AE≅CF, then BE=AB-AE, FB=BC-CF).
Be SSS theorem, ΔBDE≅ΔBDF.
Answer:
He would be able to play for 5 games
Step-by-step explanation:
9 divided by 1.75 to get 5.14