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Sladkaya [172]
3 years ago
11

Use the discriminant to determine if the following quadratic equations have complex or real solution(s). If an equation has real

solution(s), determine the solution(s).
Part A: 4x^2-3x-10=0
part b x^2-14x+49=0
part c g [x]=x^2-8x-20
Part D: h[x]=x^2-9x+36
Part E: 3[x+2]^2+36=0
Mathematics
1 answer:
rjkz [21]3 years ago
6 0
It would be part D since we already know it’s variables we grab the solution and multiply them . after that you
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Michael multiplies 0.4 by a number. He records the product as 0.012. What number did Michael use? Michael used
Free_Kalibri [48]

Answer:

0.03

Step-by-step explanation:

Calculation for What number did Michael used

Using this formula

Number used=Number of Product recorded/Number multiplied

Let plug in the formula

Number used =0.012/0.4

Number used =0.03

CHECK: 0.4*0.03=0.012

Therefore the number that Michael used is 0.03

5 0
3 years ago
If 19 represents 228 gallons, what is the value of 6 units
levacccp [35]

Answer:

72 gallons

Step-by-step explanation:

we know that

19 units represent 228 gallons

so

using proportion

Find out how many gallons represent 6 units

Let

x ---> the number of gallons for 6 units

\frac{228}{19}\ \frac{gallons}{units} =\frac{x}{6}\ \frac{gallons}{units}\\\\x=228(6)/19\\\\x=72\ gallons

7 0
3 years ago
Which figure is the pre-image? Which figure is the image after the first transformation? Which figure is the image after the sec
Delvig [45]

Answer:

I believe the red one is the first image then the blue then the green because they show the prime sign

Step-by-step explanation:

4 0
3 years ago
What is |x|+|y|, if x=5 and y=-7<br><br> A. 2 <br> B. 12<br> C. -2<br> D. -12
Stells [14]

Answer:

the correct answer is b

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.
gizmo_the_mogwai [7]

Answer:

When y=32, x=16.5

Step-by-step explanation:

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

We are given:

x varies inversely with y

We can write it as: x\:\alpha \:\frac{1}{y}

x=\frac{k}{y}

We have x = 132, when y=4

We can find value of k by using these values

x=\frac{k}{y}\\132=\frac{k}{4}\\k=132*4\\k=528

We need to find x when y=32

x=\frac{k}{y}\\x=\frac{528}{32}\\x=16.5

So, when y=32, x=16.5

6 0
3 years ago
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